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  • Data Structure Linked List: Function to check if a singly linked list is palindrome

    http://www.geeksforgeeks.org/function-to-check-if-a-singly-linked-list-is-palindrome/

    这里的reverse可以reverse整个list,这样空间需求就是O(n),不如这个网页写的O(1)的方法

     1 #include <iostream>
     2 #include <vector>
     3 #include <algorithm>
     4 #include <queue>
     5 #include <stack>
     6 #include <string>
     7 #include <fstream>
     8 #include <map>
     9 #include <set>
    10 using namespace std;
    11 
    12 struct node {
    13     int data;
    14     node *next;
    15     node() : data(0), next(NULL) { }
    16     node(int d) : data(d), next(NULL) { }
    17 };
    18 
    19 void push(node* &head, int k) {
    20     node *new_node = new node(k);
    21     new_node->next = head;
    22     head = new_node;
    23 }
    24 
    25 void print(node* head) {
    26     while (head) {
    27         cout << head->data << " ";
    28         head = head->next;
    29     }
    30     cout << endl;
    31 }
    32 
    33 void reverselist(node *&head) {
    34     if (!head) return;
    35     node *cur = head;
    36     node *next = head->next;
    37     if (!next) return;
    38     reverselist(next);
    39     cur->next->next = cur;
    40     cur->next = NULL;
    41     head = next;
    42 }
    43 
    44 bool compare(node *first, node* second) {
    45     while (first && second) {
    46         if (first->data != second->data) return false;
    47         first = first->next;
    48         second = second->next;
    49     }
    50     return first == NULL && second == NULL;
    51 }
    52 
    53 bool palin(node *head) {
    54     if (!head || !head->next) return true;
    55     node *p, *q, *pre;
    56     p = q = pre = head;
    57     node *midnode = NULL;
    58     while (q && q->next) {
    59         q = q->next->next;
    60         pre = p;
    61         p = p->next;
    62     }
    63     if (q) { //odd number
    64         midnode = p;
    65         p = p->next;
    66     }
    67     node *second = p;
    68     pre->next = NULL;
    69     reverselist(second);
    70     bool ans = compare(head, second);
    71     reverselist(second);
    72     if (midnode) {
    73         pre->next = midnode;
    74         midnode->next = second;
    75     }
    76     else pre->next = second;
    77     return ans;
    78 }
    79 
    80 int main() {
    81     node *head = NULL;
    82     push(head, 1);
    83     push(head, 2);
    84     push(head, 3);
    85     push(head, 3);
    86     push(head, 2);
    87     push(head, 1);
    88     if (palin(head)) cout << "yes" << endl;
    89     else cout << "no" << endl;
    90     print(head);
    91     return 0;
    92 }

     recursive的法子很巧

     1 #include <iostream>
     2 #include <vector>
     3 #include <algorithm>
     4 #include <queue>
     5 #include <stack>
     6 #include <string>
     7 #include <fstream>
     8 #include <map>
     9 #include <set>
    10 using namespace std;
    11 
    12 struct node {
    13     int data;
    14     node *next;
    15     node() : data(0), next(NULL) { }
    16     node(int d) : data(d), next(NULL) { }
    17 };
    18 
    19 void push(node* &head, int k) {
    20     node *new_node = new node(k);
    21     new_node->next = head;
    22     head = new_node;
    23 }
    24 
    25 void print(node* head) {
    26     while (head) {
    27         cout << head->data << " ";
    28         head = head->next;
    29     }
    30     cout << endl;
    31 }
    32 
    33 bool palinhelp(node *&left, node *right) {
    34     if (right == NULL) return true;
    35     bool palin1 = palinhelp(left, right->next);
    36     if (!palin1) return false;
    37     bool palin2 = right->data == left->data;
    38     left = left->next;
    39     return palin2;
    40 }
    41 
    42 bool palin(node *head) {
    43     return palinhelp(head, head);
    44 }
    45 
    46 int main() {
    47     node *head = NULL;
    48     push(head, 1);
    49     push(head, 2);
    50     push(head, 3);
    51     push(head, 3);
    52     push(head, 2);
    53     push(head, 1);
    54     if (palin(head)) cout << "yes" << endl;
    55     else cout << "no" << endl;
    56     print(head);
    57     return 0;
    58 }
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3655620.html
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