Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3
, return true
.
http://oj.leetcode.com/problems/search-a-2d-matrix/
public class Solution { public boolean searchMatrix(int[][] matrix, int target) { int row=matrix.length; int col=matrix[0].length; if(row==0||col==0||matrix[0][0]>target||matrix[row-1][col-1]<target){ return false; } int in =-1; for(int i=1;i<row;i++){ if(matrix[i][0]>target){ in = i-1; break; } } if(in==-1){ in = row-1; } for(int x=0;x<col;x++){ if(matrix[in][x]==target){ return true; } } return false; } }