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  • 基础算法——二叉树

    /*************************************************************************
        > File Name: binary_tree.cpp
        > Author: xinyang
        > Mail: xuechen.xy@gmail.com 
        > Created Time: Fri 02 Oct 2015 05:24:25 PM CST
     ************************************************************************/
    #include <iostream>
    #include <stack>
    #include <queue>
    using namespace std;
    
    /*
     * 二叉树节点
     */
    struct Node {
        int value;
        Node *lchild, *rchild;
        Node *next;
    
        Node (int x) {
            value = x;
            lchild = NULL;
            rchild = NULL;
            next = NULL;
        }
    };
    
    /*
     * 往二叉树中插入节点
     */
    Node *insert(Node *T, int x) {
        if (T == NULL) {
            T = new Node(x);
        } else if (T->value > x) {
            T->lchild = insert(T->lchild, x);
        } else if (T->value < x) {
            T->rchild = insert(T->rchild, x);
        }
    
        return T;
    }
    
    /*
     * 前序遍历(递归)
     */
    void pre_order_recur(Node *T) {
        cout << T->value << ' ';
        if (T->lchild != NULL) {
            pre_order_recur(T->lchild);
        } 
        if (T->rchild != NULL) {
            pre_order_recur(T->rchild);
        }
    }
    
    /*
     * 前序遍历(非递归)
     */
    void pre_order_iter(Node *T) {
        if (T == NULL) {
            return;
        }
    
        Node *tmp = T;
        stack<Node *> S;
        while (tmp != NULL || !S.empty()) {
            while (tmp != NULL) {
                S.push(tmp);
                cout << tmp->value << ' ';
                tmp = tmp->lchild;
            }
            if (!S.empty()) {
                tmp = S.top();
                S.pop();
                tmp = tmp->rchild;
            }
        }
    }
    
    /*
     * 中序遍历(递归)
     */
    void in_order_recur(Node *T) {
        if (T->lchild != NULL) {
            in_order_recur(T->lchild);
        }
        cout << T->value << ' ';
        if (T->rchild != NULL) {
            in_order_recur(T->rchild);
        }
    }
    
    /*
     * 中序遍历(非递归)
     */
    void in_order_iter(Node *T) {
        if (T == NULL) {
            return ;
        }
    
        Node *tmp = T;
        stack<Node *> S;
        while (tmp != NULL || !S.empty()) {
            while (tmp != NULL) {
                S.push(tmp);
                tmp = tmp->lchild;
            }
            if (!S.empty()) {
                tmp = S.top();
                S.pop();
                cout << tmp->value << ' ';
                tmp = tmp->rchild;
            }
        }
    }
    
    /*
     * 后序遍历(递归)
     */
    void post_order_recur(Node *T) {
        if (T->lchild != NULL) {
            post_order_recur(T->lchild);
        }
        if (T->rchild != NULL) {
            post_order_recur(T->rchild);
        }
        cout << T->value << ' ';
    }
    /*
     * 后序遍历(非递归)
     */
    void post_order_iter(Node *T) {
        if (T == NULL) {
            return;
        }
    
        Node *pre = NULL, *cur = NULL;
        stack<Node *> S;
        S.push(T);
        while (!S.empty()) {
            cur = S.top();
            if ((cur->lchild == NULL && cur->rchild == NULL)
                    || (pre != NULL && (pre == cur->lchild || pre == cur->rchild))) {
                cout << cur->value << ' ';
                S.pop();
                pre = cur;
            } else {
                if (cur->rchild != NULL) {
                    S.push(cur->rchild);
                }
                if (cur->lchild != NULL) {
                    S.push(cur->lchild);
                }
            }
        }
    }
    
    /*
     * 层次遍历
     */
    void level_order(Node *T) {
        if (T == NULL) {
            return;
        }
    
        Node *tmp = T;
        queue<Node *> Q;
        Q.push(tmp);
        while (!Q.empty()) {
            tmp = Q.front();
            Q.pop();
            cout << tmp->value << ' ';
            if (tmp->lchild != NULL) {
                Q.push(tmp->lchild);
            }
            if (tmp->rchild != NULL) {
                Q.push(tmp->rchild);
            }
        }
    }
    
    /*
     * 按行打印(换行)
     */
    void level_order_line(Node *T) {
        if (T == NULL) {
            return;
        }
    
        int cur = 0, last = 0;
        Node *tmp = T;
        queue<Node *> Q;
        Q.push(tmp);
        cur = 1;
        while (!Q.empty()) {
            last = cur;
            while (last--) {
                tmp = Q.front();
                Q.pop();
                cout << tmp->value << ' ';
                if (tmp->lchild != NULL) {
                    Q.push(tmp->lchild);
                } 
                if (tmp->rchild != NULL) {
                    Q.push(tmp->rchild);
                }
            }
            cur = Q.size();
            cout << endl;
        }
    }
    
    /*
     * 按行打印(之字形)
     */
    void level_order_s(Node *T) {
        if (T == NULL) {
            return;
        }
    
        stack<Node *> levels[2];
        int current = 0, next = 1;
        Node *tmp = T;
        levels[current].push(tmp);
        while (!levels[current].empty() || !levels[next].empty()) {
            tmp = levels[current].top();
            levels[current].pop();
            cout << tmp->value << ' ';
    
            if (current == 0) {
                if (tmp->lchild != NULL) {
                    levels[next].push(tmp->lchild);
                }
                if (tmp->rchild != NULL) {
                    levels[next].push(tmp->rchild);
                }
            } else {
                if (tmp->rchild != NULL) {
                    levels[next].push(tmp->rchild);
                }
                if (tmp->lchild != NULL) {
                    levels[next].push(tmp->lchild);
                }
            }
    
            if (levels[current].empty()) {
                cout << endl;
                current = 1 - current;
                next = 1 - next;
            }
        }
    }
    /*
     * 高度(递归)
     */
    int height_recur(Node *T) {
        if (T == NULL) {
            return 0;
        }
    
        int left = height_recur(T->lchild);
        int right = height_recur(T->rchild);
        return left > right ? (left + 1) : (right + 1);
    }
    /*
     * 高度(非递归)
     */
    int height_iter(Node *T) {
        if (T == NULL) {
            return 0;
        }
    
        Node *tmp = T;
        queue<Node *> Q;
        Q.push(tmp);
        while (!Q.empty()) {
            tmp = Q.front();
            Q.pop();
            if (tmp->lchild != NULL) {
                Q.push(tmp->lchild);
            }
            if (tmp->rchild != NULL) {
                Q.push(tmp->rchild);
            }
        }
    
        Node *m = tmp, *n = T;
        int h = 0;
        while (m != n) {
            Q.push(n);
            while (!Q.empty()) {
                tmp = Q.front();
                Q.pop();
                if (tmp->lchild == m || tmp->rchild == m) {
                    ++h;
                    m = tmp;
                    break;
                }
                if (tmp->lchild != NULL) {
                    Q.push(tmp->lchild);
                }
                if (tmp->rchild != NULL) {
                    Q.push(tmp->rchild);
                }
            }
        }
        return h + 1;
    }
    /*
     * 宽度
     */
    int width(Node *T) {
        if (T == NULL) {
            return 0;
        }
    
        Node *tmp = T;
        queue<Node *> Q;
        Q.push(tmp);
        int last_width = 1, last_width_tmp = 1;
        int width = 1, cur_width = 1;
        while (!Q.empty()) {
            last_width_tmp = last_width;
            while (last_width_tmp--) {
                tmp = Q.front();
                Q.pop();
                if (tmp->lchild != NULL) {
                    Q.push(tmp->lchild);
                }
                if (tmp->rchild != NULL) {
                    Q.push(tmp->rchild);
                }
            }
            cur_width = Q.size();
            width = cur_width > width ? cur_width : width;
            last_width = cur_width;
        }
        return width;
    }
    
    /*
     * 平衡二叉树判断1
     */
    bool is_balanced1(Node *T) {
        if (T == NULL) {
            return true;
        }
    
        int left = height_recur(T->lchild);
        int right = height_recur(T->rchild);
        int diff = left - right;
        if (diff > 1 || diff < -1) {
            return false;
        } else {
            return is_balanced1(T->lchild)
                && is_balanced1(T->rchild);
        }
    }
    /*
     * 最小高度
     */
    int min_depth(Node *T) {
        if (T == NULL) {
            return 0;
        }
    
        return 1 + min(min_depth(T->lchild), 
                min_depth(T->rchild));
    }
    /*
     * 最大高度
     */
    int max_depth(Node *T) {
        if (T == NULL) {
            return 0;
        }
    
        return 1 + max(max_depth(T->lchild), 
                max_depth(T->rchild));
    }
    
    /*
     * 平衡二叉树判断2
     */
    bool is_balanced2(Node *T) {
        if (T == NULL) {
            return true;
        }
    
        int min_h = min_depth(T);
        int max_h = max_depth(T);
        return max_h - min_h <= 1;
    }
    
    /*
     * 判断两棵二叉树是否相等
     */
    bool is_equal(Node *T1, Node *T2) {
        if (T1 == NULL && T2 == NULL) {
            return true;
        }
    
        if (T1 == NULL || T2 == NULL) {
            return false;
        }
    
        if (T1->value == T2->value) {
            return is_equal(T1->lchild, T2->lchild)
                && is_equal(T1->rchild, T2->rchild);
        } else {
            return false;
        }
    }
    
    /*
     * 判断两棵二叉树是否对称
     */
    bool is_symmetrical(Node *T1, Node *T2) {
        if (T1 == NULL && T2 == NULL) {
            return true;
        }
    
        if (T1 == NULL || T2 == NULL) {
            return false;
        }
    
        if (T1->value == T2->value) {
            return is_symmetrical(T1->lchild, T2->rchild)
                && is_symmetrical(T1->rchild, T2->lchild);
        } else {
            return false;
        }
    }
    
    bool is_symmetrical(Node *T) {
        if (T == NULL) {
            return true;
        }
    
        return is_symmetrical(T, T);
    }
    
    /*
     * 求一棵二叉树的镜像
     */
    Node *mirror(Node *T) {
        if (T == NULL) {
            return NULL;
        }
    
        if (T->lchild == NULL && T->rchild == NULL) {
            return T;
        }
    
        Node *tmp = T->lchild;
        T->lchild = T->rchild;
        T->rchild = tmp;
        if (T->lchild != NULL) {
            T->lchild = mirror(T->lchild);
        }
        if (T->rchild != NULL) {
            T->rchild = mirror(T->rchild);
        }
        return T;
    }
    
    /*
     * 二叉树1与2有相同的根节点,判断1是否包含2
     */
    bool does_1_has_2(Node *T1, Node *T2) {
        if (T2 == NULL) {
            return true;
        }
    
        if (T1 == NULL) {
            return false;
        }
    
        if (T1->value == T2->value) {
            return does_1_has_2(T1->lchild, T2->lchild)
                && does_1_has_2(T1->rchild, T2->rchild);
        } else {
            return false;
        }
    }
    
    /*
     * 判断二叉树1中是否包含二叉树2
     */
    bool has_subtree(Node *T1, Node *T2) {
        bool result = false;
        if (T2 == NULL) {
            return true;
        }
    
        if (T1 == NULL) {
            return false;
        }
    
        if (T1->value == T2->value) {
            result = does_1_has_2(T1, T2);
        }
    
        if (false == result) {
            result = has_subtree(T1->lchild, T2);
        }
    
        if (false == result) {
            result = has_subtree(T1->rchild, T2);
        }
    
        return result;
    }
    
    /*
     * 判断一棵完美二叉树
     */
    bool is_perfect_tree(Node *T) {
        if (T == NULL) {
            return true;
        }
    
        queue<Node *> Q;
        Node *tmp = T;
        Q.push(tmp);
        while (!Q.empty()) {
            tmp = Q.front();
            Q.pop();
            if ((tmp->lchild != NULL && tmp->rchild == NULL) 
                    || (tmp->lchild == NULL && tmp->rchild != NULL)) {
                return false;
            }
            if (tmp->lchild != NULL) {
                Q.push(tmp->lchild);
            }
            if (tmp->rchild != NULL) {
                Q.push(tmp->rchild);
            }
        }
        return true;
    }
    
    /*
     * 判断一棵完全二叉树
     */
    bool is_complete_tree(Node *T) {
        if (T == NULL) {
            return true;
        }
    
        queue<Node *> Q;
        Node *tmp = T;
        Q.push(tmp);
        while (!Q.empty()) {
            tmp = Q.front();
            Q.pop();
            if (tmp == NULL) {
                break;
            }
            Q.push(tmp->lchild);
            Q.push(tmp->rchild);
        }
    
        while (!Q.empty()) {
            tmp = Q.front();
            Q.pop();
            if (tmp != NULL) {
                return false;
            }
        }
        return true;
    }
    
    /*
     * 由前序遍历以及中序遍历序列构建二叉树
     */
    int pre[] = {3, 1, 2, 8, 7, 5, 4, 6, 9};
    int in[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
    Node *build_tree(int s1, int e1, int s2, int e2) {
        Node *ret = new Node(pre[s1]);
        int rootIdx;
        int i;
        for (i = s2; i <= e2; ++i) {
            if (in[i] == pre[s1]) {
                rootIdx = i;
                break;
            }
        }
    
        if (i == e2 + 1) {
            return NULL;
        }
    
        if (rootIdx != s2) {
            ret->lchild = build_tree(s1 + 1, s1 + rootIdx - s2, 
                    s2, rootIdx - 1);
        }
    
        if (rootIdx != e2) {
            ret->rchild = build_tree(s1 + rootIdx - s2 + 1, 
                    e1, rootIdx + 1, e2);
        }
    
        return ret;
    }
    
    /*
     * 判断是否是BST的后序序列
     */
    bool verify_sequence_of_BST(int A[], int n) {
        if (A == NULL || n <= 0) {
            return true;
        }
    
        int root = A[n - 1];
        int i = 0;
        for (; i < n - 1; ++i) {
            if (A[i] > root) {
                break;
            }
        }
    
        int j = i;
        for (; j < n - 1; ++j) {
            if (A[j] < root) {
                return false;
            }
        }
    
        bool left = true;
        if (i > 0) {
            left = verify_sequence_of_BST(A, i);
        }
        bool right = true;
        if (i < n - 1) {
            right = verify_sequence_of_BST(A + i, n - i - 1);
        }
        return left && right;
    }
    
    /*
     * 从二叉树中查找和为定值的路径
     */
    void find_path(Node *T, int sum, vector<int> &path, int cur_sum) {
        cur_sum += T->value;
        path.push_back(T->value);
        bool is_leaf = T->lchild == NULL && T->rchild == NULL;
        if (is_leaf == true && cur_sum == sum) {
            for (int i = 0; i < path.size(); ++i) {
                cout << path[i] << ' ';
            }
            cout << endl;
        }
    
        if (T->lchild != NULL) {
            find_path(T->lchild, sum, path, cur_sum);
        }
    
        if (T->rchild != NULL) {
            find_path(T->rchild, sum, path, cur_sum);
        }
        path.pop_back();
    }
    
    void find_path(Node *T, int sum) {
        if (T == NULL) {
            return;
        }
    
        int cur_sum = 0;
        vector<int> path;
        find_path(T, sum, path, cur_sum);
    }
    
    /*
     * 将二叉搜索树转换为双向链表
     */
    void convert_node(Node *T, Node **last_node) {
        if (T == NULL) {
            return ;
        }
    
        if (T->lchild != NULL) {
            convert_node(T->lchild, last_node);
        }
    
        T->lchild = *last_node;
        if (*last_node != NULL) {
            (*last_node)->rchild = T;
        }
        *last_node = T;
    
        if (T->rchild != NULL) {
            convert_node(T->rchild, last_node);
        }
    }    
    
    Node *convert(Node *T) {
        Node *last_node = NULL;
        convert_node(T, &last_node);
        Node *head = last_node;
        while (head != NULL && head->lchild != NULL) {
            head = head->lchild;
        }
        return head;
    }
    
    /*
     * 找出BST中第k个节点
     */
    Node *kth_node_core(Node *T, int &k) {
        Node *target = NULL;
        if (T->lchild != NULL) {
            target = kth_node_core(T->lchild, k);
        }
    
        if (target == NULL) {
            if (k == 1) {
                target = T;
            }
            --k;
        }
    
        if (target == NULL && T->rchild != NULL) {
            target = kth_node_core(T->rchild, k);
        }
        return target;
    }
    
    Node *kth_node(Node *T, int k) {
        if (T == NULL || k <= 0) {
            return NULL;
        }
    
        return kth_node_core(T, k);
    }
    
    /*
     * 获取二叉树中两个节点的最大距离(边个数)
     */
    struct RESULT {
        int max_distance;
        int max_depth;
    };
    
    RESULT get_max_distance(Node *T) {
        if (T == NULL) {
            RESULT empty = {0, -1};
            return empty;
        }
        
        RESULT lhs = get_max_distance(T->lchild);
        RESULT rhs = get_max_distance(T->rchild);
        RESULT ret;
        ret.max_depth = max(lhs.max_depth + 1, rhs.max_depth + 1);
        ret.max_distance = max(max(lhs.max_distance, rhs.max_distance),
                lhs.max_depth + rhs.max_depth + 2);
        return ret;
    }
    
    /*
     * 获取两个节点的最低公共祖先(递归)
     */
    Node *common_parent1(Node *T, Node *node1, Node *node2) {
        if (T == NULL) {
            return NULL;
        }
    
        if (node1 == T || node2 == T) {
            return T;
        }
    
        Node *left = common_parent1(T->lchild, node1, node2);
        Node *right = common_parent1(T->rchild, node1, node2);
        if (left == NULL) {
            return right;
        } else if (right == NULL) {
            return left;
        } else {
            return T;
        }
    }
    
    /*
     * 获取两个节点的最低公共祖先(迭代)
     */
    bool find_node(Node *T, Node *node, vector<Node *> &path) {
        if (T == NULL) {
            return false;
        }
    
        path.push_back(T);
        if (T == node) {
            return true;
        }
    
        bool found = false;
        found = find_node(T->lchild, node, path);
        if (false == found) {
            found = find_node(T->rchild, node, path);
        }
        if (false == found) {
            path.pop_back();
        }
        return found;
    }
    
    Node *common_parent2(Node *T, Node *node1, Node *node2) {
        Node *ret = NULL;
        vector<Node *> path1;
        vector<Node *> path2;
        bool has_node1 = find_node(T, node1, path1);
        bool has_node2 = find_node(T, node2, path2);
        if (false == has_node1 || false == has_node2) {
            return T;
        }
    
        int L1 = path1.size();
        int L2 = path2.size();
        for (int i = 0, j = 0; i != L1 && j != L2; ++i, ++j) {
            if (path1[i] != path2[j]) {
                break;
            }
            ret= path1[i];
        }
        return ret;
    }
    
    /*
     * 判断一个节点是否是叶节点,如果是,求出根节点到该节点的路径
     */
    bool find_leaf_node(Node *T, Node *node, vector<Node *> &path) {
        if (T == NULL) {
            return false;
        }
    
        path.push_back(T);
        bool is_leaf = T->lchild == NULL && T->rchild == NULL;
        if (true == is_leaf && T == node) {
            return true;
        }
    
        bool found = false;
        found = find_leaf_node(T->lchild, node, path);
        if (false == found) {
            found = find_leaf_node(T->rchild, node, path);
        }
        if (false == found) {
            path.pop_back();
        }
        return found;
    }
    
    /*
     * 在一棵完全二叉树中使用next指针链接旁边的节点
     */
    void connect_complete_tree(Node *T) {
        if (T == NULL) {
            return ;
        }
    
        Node *tmp = T;
        Node *first = NULL;
        while (tmp != NULL) {
            if (first == NULL) {
                first = tmp->lchild;
            }
            if (tmp->lchild != NULL) {
                tmp->lchild->next = tmp->rchild;
            } else {
                break;
            }
            if (tmp->next != NULL) {
                tmp->rchild->next = tmp->next->lchild;
                tmp = tmp->next;
                continue;
            } else {
                tmp = first;
                first = NULL;
            }
        }
    }
    
    /*
     * 在一棵普通二叉树中使用next指针链接旁边的节点
     */
    void connext_normal_tree(Node *T) {
        if (T == NULL) {
            return ;
        }
    
        Node *tmp = T;
        Node *first = NULL, *last = NULL;
        while (tmp != NULL) {
            if (first == NULL) {
                if (tmp->lchild != NULL) {
                    first = tmp->lchild;
                } else if (tmp->rchild != NULL) {
                    first = tmp->rchild;
                }
                if (tmp->lchild != NULL) {
                    if (last != NULL) {
                        last->next = tmp->lchild;
                    }
                    last = tmp->next;
                }
                if (tmp->rchild != NULL) {
                    
                    if (last != NULL) {
                        last->next = tmp->rchild;
                    } 
                    last = tmp->next;
                }
                if (tmp->next != NULL) {
                    tmp = tmp->next;
                } else {
                    tmp = first;
                    first = NULL;
                    last = NULL;
                }
            }
        }
    }
    
    /*
     * 将一个排过序的链表转成一棵BST
     */
    struct ListNode {
        int value;
        ListNode *next;
        ListNode(int x) {
            value = x;
            next = NULL;
        }
    };
    
    Node *build_from_list(ListNode *start, ListNode *end) {
        if (start == end) {
            return NULL;
        }
    
        ListNode *fast = start, *slow = start;
        while (fast != end && fast->next != end) {
            slow = slow->next;
            fast = fast->next->next;
        }
    
        Node *ret = new Node(slow->value);
        
        ret->lchild = build_from_list(start, slow);
        ret->rchild = build_from_list(slow->next, end);
    
        return ret;
    }
    
    Node *sorted_list_to_BST(ListNode *head) {
        return build_from_list(head, NULL);
    }
    
    /*
     * 将一个排过序的数组转换成一棵BST
     */
    Node *build_from_array(const vector<int> &num, int start, int end) {
        if (start >= end) {
            return NULL;
        }
    
        int mid = (start + end) / 2;
        Node *ret = new Node(num[mid]);
    
        ret->lchild = build_from_array(num, start, mid);
        ret->rchild = build_from_array(num, mid + 1, end);
    
        return ret;
    }
    
    Node *sort_array_to_BST(const vector<int> &num) {
        return build_from_array(num, 0, num.size());
    }
    
    /*
     * 将一颗二叉树磨平
     */
    void flatten(Node *T) {
        if (T == NULL) {
            return;
        }
    
        stack<Node *> S;
        Node *p = new Node (0);
        Node *ret = p;
    
        S.push(T);
        while (!S.empty()) {
            Node *tmp = S.top();
            S.pop();
    
            p->rchild = tmp;
            p = tmp;
    
            if (tmp->rchild != NULL) {
                S.push(tmp->rchild);
                tmp->rchild = NULL;
            }
            if (tmp->lchild != NULL) {
                S.push(tmp->lchild);
                tmp->lchild = NULL;
            }
        }
    }
    
    /*
     * 判断一棵二叉树是否是BST
     */
    #define MIN 0x80000000
    #define MAX 0x7fffffff
    bool is_valid_BST_core(Node *T, int min, int max) {
        if (T == NULL) {
            return true;
        }
    
        if (T->value < min || T->value > max) {
            return false;
        }
    
        return is_valid_BST_core(T->lchild, min, T->value)
            && is_valid_BST_core(T->rchild, T->value, max);
    
    }
    
    bool is_valid_BST(Node *T) {
        return is_valid_BST_core(T, MIN, MAX);
    }
    
    int main() {
        int A[] = {3, 8, 7, 1, 2, 5, 6, 4, 9};
        Node *T = NULL;
        for (int i = 0; i < 9; ++i) {
            T = insert(T, A[i]);
        }
    
        cout << "pre_order_recur" << endl;
        pre_order_recur(T);
        cout << endl;
        cout << "pre_order_iter" << endl;
        pre_order_iter(T);
        cout << endl << endl;
    
        cout << "in_order_recur" << endl;
        in_order_recur(T);
        cout << endl;
        cout << "in_order_iter" << endl;
        in_order_iter(T);
        cout << endl << endl;
    
        cout << "post_order_recur" << endl;
        post_order_recur(T);
        cout << endl;
        cout << "post_order_iter" << endl;
        post_order_iter(T);
        cout << endl << endl;
    
        cout << "level_order" << endl;
        level_order(T);
        cout << endl << endl;
        cout << "level_order_line" << endl;
        level_order_line(T);
        cout << endl << endl;
    
        cout << "level_order_s" << endl;
        level_order_s(T);
        cout << endl << endl;
    
        cout << "height_recur" << endl;
        cout << height_recur(T) << endl;
        cout << "height_iter" << endl;
        cout << height_iter(T);
        cout << endl << endl;
    
        cout << "width" << endl;
        cout << width(T);
        cout << endl << endl;
    
        // if (true == is_balanced1(T)) {
        if (true == is_balanced2(T)) {
            cout << "is balanced" << endl << endl;
        } else {
            cout << "is not balanced" << endl << endl;
        }
    
        if (true == is_equal(T, T)) {
            cout << "is equal" << endl << endl;
        } else {
            cout << "is not equal" << endl << endl;
        }
    
        /*
        Node *T1 = mirror(T);
        // if (true == is_symmetrical(T)) {
        if (true == is_symmetrical(T, T1)) {
            cout << "is symmetrical" << endl << endl;
        } else {
            cout << "is not symmetrical" << endl << endl;
        }
        */
    
        Node *T2 = T->lchild;
        if (true == has_subtree(T, T2)) {
            cout << "1 has 2" << endl << endl;
        } else {
            cout << "1 has no 2" << endl << endl;
        }
    
        if (true == is_perfect_tree(T)) {
            cout << "is pefect tree" << endl << endl;
        } else {
            cout << "is not perfect tree" << endl << endl;
        }
    
        if (true == is_complete_tree(T)) {
            cout << "is complete tree" << endl << endl;
        } else {
            cout << "is not complete tree" << endl << endl;
        }
    
        Node *post = build_tree(0, 8, 0, 8);
        post_order_iter(post);
        cout << endl << endl;
    
        int B[] = {2, 1, 4, 6, 5, 7, 9, 8, 3};
        if (true == verify_sequence_of_BST(B, 9)) {
            cout << "is valid BST sequence" << endl << endl;
        } else {
            cout << "is not valid BST sequence" << endl << endl;
        }
    
        cout << "find path in a tree with confirmed sum" << endl;
        find_path(T, 27);
        cout << endl;
    
        /*
        cout << "convert a tree into a link list" << endl;
        Node *convert_ret = convert(T);
        while (convert_ret != NULL) {
            cout << convert_ret->value << ' ';
            convert_ret = convert_ret->rchild;
        }
        cout << endl << endl;
        */
    
        cout << "2th node's value" << endl;
        Node *kth_ret = kth_node(T, 2);
        cout << kth_ret->value << endl << endl;
    
        cout << "max distance" << endl;
        RESULT max_ret = get_max_distance(T);
        cout << max_ret.max_distance << endl << endl;
    
        cout << "common parent of node1 and node2" << endl;
        Node *node1 = T->lchild, *node2 = T->rchild;
        cout << "node1: " << node1->value << ", node2: " << node2->value << endl;
        Node *common_ret = common_parent1(T, node1, node2);
        // Node *common_ret = common_parent2(T, node1, node2);
        cout << common_ret->value << endl << endl;
    
        cout << "find a path to leaf_node" << endl;
        Node *leaf = T->lchild->rchild;
        vector<Node *> path;
        if (true == find_leaf_node(T, leaf, path)) {
            cout << "path is" << endl;
            for (int i = 0; i < path.size(); ++i) {
                cout << path[i]->value << ' ';
            }
            cout << endl << endl;
        } else {
            cout << "no path" << endl << endl;
        }
    
        /*
        flatten(T);
        pre_order_recur(T);
        cout << endl;
        in_order_recur(T);
        cout << endl << endl;
        */
    
        if (true == is_valid_BST(T)) {
            cout << "is valid bst" << endl << endl;
        } else {
            cout << "is not valid bst" << endl << endl;
        }
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/yiyi-xuechen/p/4858741.html
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