Problem Description
Are you excited when you see the title "AC" ? If the answer is YES , AC it ;
You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .
You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .
Input
In the first line , there is a integer T indicates the number of test cases.
Then T cases follows in the T lines.
Each case contains a character 'A' or 'C', two integers represent n and m. (1<=n,m<=10)
Then T cases follows in the T lines.
Each case contains a character 'A' or 'C', two integers represent n and m. (1<=n,m<=10)
Output
For each case , if the character is 'A' , calculate A(m,n),and if the character is 'C' , calculate C(m,n).
And print the answer in a single line.
And print the answer in a single line.
Sample Input
2
A 10 10
C 4 2
Sample Output
3628800
6
Author
linle
Source
题目简述:给定两个值n、m,求这俩数的组合值和排列值!n,m的范围都很不大,所以这题不难!
View Code

1 #include <stdio.h> 2 3 int AA( int n, int m ) 4 { 5 int mul = 1, i; 6 for( i = 0; i <= (m-1); i++ ) 7 mul *= (n - i); 8 return mul; 9 } 10 11 int main() 12 { 13 int tcase, n, m; 14 char c; 15 scanf( "%d", &tcase ); 16 getchar(); 17 while( tcase-- ) 18 { 19 scanf( "%c %d %d", &c, &n, &m ); 20 getchar(); 21 if( c == 'A' ) 22 printf( "%d\n", AA(n,m) ); 23 else if( c == 'C' ) 24 printf( "%d\n",AA(n,m)/AA(m,m) ); 25 } 26 return 0; 27 }