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  • CodeForce 424C Magic Formulas


    这个题就是求出给的公式的结果。


    仅仅要知道异或运算满足交换律跟结合律即可了。之后就是化简公式。


    #include<map>
    #include<string>
    #include<cstring>
    #include<cstdio>
    #include<cstdlib>
    #include<cmath>
    #include<queue>
    #include<vector>
    #include<iostream>
    #include<algorithm>
    #include<bitset>
    #include<climits>
    #include<list>
    #include<iomanip>
    #include<stack>
    #include<set>
    using namespace std;
    int psum[1000010];
    int main()
    {
    	int n;
    	cin>>n;
    	int ans=0;
    	for(int i=0;i<n;i++)
    	{
    		int t;
    		scanf("%d",&t);
    		ans^=t;
    	}
    	for(int i=1;i<n;i++)
    		psum[i]=i^psum[i-1];
    	for(int i=1;i<=n;i++)
    	{
    		int t=n/i;
    		if(t&1)
    			ans^=psum[i-1];
    		t=n%i;
    		ans^=psum[t];
    	}
    	cout<<ans;
    }



    Magic Formulas
    time limit per test
     2 seconds
    memory limit per test
     256 megabytes
    input
     standard input
    output
     standard output

    People in the Tomskaya region like magic formulas very much. You can see some of them below.

    Imagine you are given a sequence of positive integer numbers p1p2, ..., pn. Lets write down some magic formulas:

    Here, "mod" means the operation of taking the residue after dividing.

    The expression  means applying the bitwise xor (excluding "OR") operation to integers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by "^", in Pascal — by "xor".

    People in the Tomskaya region like magic formulas very much, but they don't like to calculate them! Therefore you are given the sequence p, calculate the value of Q.

    Input

    The first line of the input contains the only integer n (1 ≤ n ≤ 106). The next line contains n integers: p1, p2, ..., pn (0 ≤ pi ≤ 2·109).

    Output

    The only line of output should contain a single integer — the value of Q.

    Sample test(s)
    input
    3
    1 2 3
    
    output
    3

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  • 原文地址:https://www.cnblogs.com/yjbjingcha/p/6963482.html
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