Telephone Number

A telephone number is a sequence of exactly 11 digits, where the first digit is 8. For example, the sequence 80011223388 is a telephone number, but the sequences 70011223388 and 80000011223388 are not.

You are given a string ss of length nn, consisting of digits.

In one operation you can delete any character from string ss. For example, it is possible to obtain strings 112, 111 or 121 from string 1121.

You need to determine whether there is such a sequence of operations (possibly empty), after which the string ss becomes a telephone number.

Input

The first line contains one integer tt (1≤t≤1001≤t≤100) — the number of test cases.

The first line of each test case contains one integer nn (1≤n≤1001≤n≤100) — the length of string ss.

The second line of each test case contains the string ss (|s|=n|s|=n) consisting of digits.

Output

For each test print one line.

If there is a sequence of operations, after which ss becomes a telephone number, print YES.

Otherwise, print NO.

Example

Input

2
13
7818005553535
11
31415926535

Output

YES
NO

Note

In the first test case you need to delete the first and the third digits. Then the string 7818005553535 becomes 88005553535

这道题就是判断11位的手机号，并且是以8开头；

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,k,i;
        cin>>n;
        char a[110];
        cin>>a;
        for(i=0;i<n;i++)
        {
            if(a[i]=='8')
            {
                k=i;//标记第一次出现8的位置
                break;
            }
        }
        if(n-i<11)
            cout<<"NO"<<endl;
        else
            cout<<"YES"<<endl;
    }
    return 0;
}

重点注意k的标记，后面if条件必须是n-i，一定不能是n-k，原因自己想想。。。。