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  • spoj 375 QTREE

    题目链接

    给一棵树, 每条边有权值, 两种操作, 一种是将一条边的权值改变, 一种是询问u到v路径上最大的边的权值。

    树链剖分模板。

    #include <iostream>
    #include <vector>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #include <map>
    #include <set>
    #include <string>
    #include <queue>
    #include <stack>
    #include <bitset>
    using namespace std;
    #define pb(x) push_back(x)
    #define ll long long
    #define mk(x, y) make_pair(x, y)
    #define lson l, m, rt<<1
    #define mem(a) memset(a, 0, sizeof(a))
    #define rson m+1, r, rt<<1|1
    #define mem1(a) memset(a, -1, sizeof(a))
    #define mem2(a) memset(a, 0x3f, sizeof(a))
    #define rep(i, n, a) for(int i = a; i<n; i++)
    #define fi first
    #define se second
    typedef pair<int, int> pll;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int mod = 1e9+7;
    const int inf = 1061109567;
    const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} };
    const int maxn = 10005;
    int head[maxn*2], son[maxn], sz[maxn], deep[maxn], top[maxn], w[maxn], f[maxn], cnt, num;
    int edge[maxn][3], maxx[maxn<<2];
    struct node
    {
        int to, nextt;
    }e[maxn*2];
    void init() {
        mem1(head);
        num = cnt = 0;
    }
    void add(int u, int v, int w) {
        e[num].to = v, e[num].nextt = head[u], head[u] = num++;
    }
    void dfs1(int u, int fa) {
        sz[u] = 1;
        deep[u] = deep[fa]+1;
        son[u] = -1;
        f[u] = fa;
        for(int i = head[u]; ~i; i = e[i].nextt) {
            int v = e[i].to;
            if(v == fa)
                continue;
            dfs1(v, u);
            sz[u] += sz[v];
            if(son[u]==-1||sz[v]>sz[son[u]])
                son[u] = v;
        }
    }
    void dfs2(int u, int tp) {
        w[u] = ++cnt, top[u] = tp;
        if(~son[u])
            dfs2(son[u], tp);
        for(int i = head[u]; ~i; i = e[i].nextt) {
            int v = e[i].to;
            if(v == f[u]||v == son[u])
                continue;
            dfs2(v, v);
        }
    }
    void pushUp(int rt) {
        maxx[rt] = max(maxx[rt<<1], maxx[rt<<1|1]);
    }
    void update(int p, int val, int l, int r, int rt) {
        if(l == r) {
            maxx[rt] = val;
            return ;
        }
        int m = l+r>>1;
        if(p<=m)
            update(p, val, lson);
        else
            update(p, val, rson);
        pushUp(rt);
    }
    int query(int L, int R, int l, int r, int rt) {
        if(L<=l&&R>=r) {
            return maxx[rt];
        }
        int m = l+r>>1, ret = 0;
        if(L<=m)
            ret = max(ret, query(L, R, lson));
        if(R>m)
            ret = max(ret, query(L, R, rson));
        return ret;
    }
    int find(int u, int v) {
        int f1 = top[u], f2 = top[v], ret = 0;
        while(f1 != f2) {
            if(deep[f1]<deep[f2]) {
                swap(f1, f2);
                swap(u, v);
            }
            ret = max(ret, query(w[f1], w[u], 1, cnt, 1));
            u = f[f1];
            f1 = top[u];
        }
        if(u == v)
            return ret;
        if(deep[u]>deep[v])
            swap(u, v);
        return max(ret, query(w[son[u]], w[v], 1, cnt, 1));
    }
    int main()
    {
        int t, n, u, v, val;
        cin>>t;
        while(t--) {
            scanf("%d", &n);
            init();
            deep[0] = 0;
            for(int i = 1; i<n; i++) {
                scanf("%d%d%d", &u, &v, &val);
                add(u, v, val);
                add(v, u, val);
                edge[i][0] = u, edge[i][1] = v, edge[i][2] = val;
            }
            dfs1(1, 0);
            dfs2(1, 1);
            for(int i = 1; i<n; i++) {
                if(deep[edge[i][0]]>deep[edge[i][1]]) {
                    swap(edge[i][0], edge[i][1]);
                }
                update(w[edge[i][1]], edge[i][2], 1, cnt, 1);
            }
            char s[10];
            while(scanf("%s", s)) {
                if(s[0] == 'D')
                    break;
                int x, y;
                scanf("%d%d", &x, &y);
                if(s[0]=='Q') {
                    printf("%d
    ", find(x, y));
                } else {
                    update(w[edge[x][1]], y, 1, cnt, 1);
                }
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/yohaha/p/5084462.html
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