1065. A+B and C (64bit)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#include<string.h>

int main()
{
    int i, t;
    scanf("%d", &t);
    long long a, b, c;
    for(i = 1; i <= t; i++)
    {
        scanf("%lld%lld%lld", &a, &b, &c);
        long long sum = a + b;
        if(a > 0 && b > 0 && sum < 0)
            printf("Case #%d: true
", i);
        else if(a < 0 && b < 0 && sum >= 0)
            printf("Case #%d: false
", i);
        else if(sum > c)
            printf("Case #%d: true
", i);
        else
            printf("Case #%d: false
", i);
    }
    return 0;
}