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  • 1058. A+B in Hogwarts

    1058. A+B in Hogwarts (20)

    时间限制
    50 ms
    内存限制
    65536 kB
    代码长度限制
    16000 B
    判题程序
    Standard
    作者
    CHEN, Yue

    If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

    Input Specification:

    Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

    Output Specification:

    For each test case you should output the sum of A and B in one line, with the same format as the input.

    Sample Input:
    3.2.1 10.16.27
    
    Sample Output:
    14.1.28
     1 #include<stdio.h>
     2 #include<math.h>
     3 #include<stdlib.h>
     4 #include<string.h>
     5 
     6 int main()
     7 {
     8     struct hog
     9     {
    10         int g, s, k;
    11     };
    12     hog a, b, sum;
    13     sum.g = sum.s = sum.k = 0;
    14     scanf("%d.%d.%d %d.%d.%d", &a.g, &a.s, &a.k, &b.g, &b.s, &b.k);
    15     if(a.k + b.k < 29)
    16     {
    17         sum.k = a.k + b.k;
    18     }
    19     else
    20     {
    21         sum.k = a.k + b.k - 29;
    22         sum.s++;
    23     }
    24     if(sum.s + a.s + b.s < 17)
    25     {
    26         sum.s += a.s + b.s;
    27     }
    28     else
    29     {
    30         sum.s += a.s + b.s - 17;
    31         sum.g++;
    32     }
    33     sum.g += a.g + b.g;
    34     printf("%d.%d.%d
    ", sum.g, sum.s, sum.k);
    35     return 0;
    36 }
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  • 原文地址:https://www.cnblogs.com/yomman/p/4271101.html
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