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  • sql笔试

    /*
    建表:
    dept:
    deptno(primary key),dname,loc
    emp:
    empno(primary key),ename,job,mgr,sal,deptno
    */

    1 列出emp表中各部门的部门号,最高工资,最低工资
    select max(sal) as 最高工资,min(sal) as 最低工资,deptno from emp group by deptno;

    2 列出emp表中各部门job为'CLERK'的员工的最低工资,最高工资
    select max(sal) as 最高工资,min(sal) as 最低工资,deptno as 部门号 from emp where job = 'CLERK' group by deptno;

    3 对于emp中最低工资小于1000的部门,列出job为'CLERK'的员工的部门号,最低工资,最高工资
    select max(sal) as 最高工资,min(sal) as 最低工资,deptno as 部门号 from emp as b
    where job='CLERK' and 1000>(select min(sal) from emp as a where a.deptno=b.deptno) group by b.deptno

    4 根据部门号由高而低,工资有低而高列出每个员工的姓名,部门号,工资
    select deptno as 部门号,ename as 姓名,sal as 工资 from emp order by deptno desc,sal asc

    5 写出对上题的另一解决方法
    (请补充)

    6 列出'张三'所在部门中每个员工的姓名与部门号
    select ename,deptno from emp where deptno = (select deptno from emp where ename = '张三')

    7 列出每个员工的姓名,工作,部门号,部门名
    select ename,job,emp.deptno,dept.dname from emp,dept where emp.deptno=dept.deptno

    8 列出emp中工作为'CLERK'的员工的姓名,工作,部门号,部门名
    select ename,job,dept.deptno,dname from emp,dept where dept.deptno=emp.deptno and job='CLERK'

    9 对于emp中有管理者的员工,列出姓名,管理者姓名(管理者外键为mgr)
    select a.ename as 姓名,b.ename as 管理者 from emp as a,emp as b where a.mgr is not null and a.mgr=b.empno

    10 对于dept表中,列出所有部门名,部门号,同时列出各部门工作为'CLERK'的员工名与工作
    select dname as 部门名,dept.deptno as 部门号,ename as 员工名,job as 工作 from dept,emp
    where dept.deptno *= emp.deptno and job = 'CLERK'

    11 对于工资高于本部门平均水平的员工,列出部门号,姓名,工资,按部门号排序
    select a.deptno as 部门号,a.ename as 姓名,a.sal as 工资 from emp as a
    where a.sal>(select avg(sal) from emp as b where a.deptno=b.deptno) order by a.deptno

    12 对于emp,列出各个部门中平均工资高于本部门平均水平的员工数和部门号,按部门号排序
    select count(a.sal) as 员工数,a.deptno as 部门号 from emp as a
    where a.sal>(select avg(sal) from emp as b where a.deptno=b.deptno) group by a.deptno order by a.deptno

    13 对于emp中工资高于本部门平均水平,人数多与1人的,列出部门号,人数,按部门号排序
    select count(a.empno) as 员工数,a.deptno as 部门号,avg(sal) as 平均工资 from emp as a
    where (select count(c.empno) from emp as c where c.deptno=a.deptno and c.sal>(select avg(sal) from emp as b where c.deptno=b.deptno))>1
    group by a.deptno order by a.deptno

    14 对于emp中低于自己工资至少5人的员工,列出其部门号,姓名,工资,以及工资少于自己的人数
    select a.deptno,a.ename,a.sal,(select count(b.ename) from emp as b where b.sal<a.sal) as 人数 from emp as a
    where (select count(b.ename) from emp as b where b.sal<a.sal)>5

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  • 原文地址:https://www.cnblogs.com/yongheng178/p/1264780.html
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