从内容里提取出链接和标题

比如内容格式是HTML格式的，里面有一堆的链接，希望从内容里提取出链接和标题。

如：

<a href='http://www.xx.cn/art/2017/12/26/art_8801_1776064.html' title='标题1' target="_blank"></a>        <p>2017-12-26</p>    </li>    ]]></record>
<record><![CDATA[
    <li> <a href='http://www.xx.gov.cn/art/2017/12/26/art_8801_1776063.html' title='标题2' target="_blank"></a>        <p>2017-12-26</p>    </li>    ]]></record>
<record><![CDATA[
    <li>        <a href='http://www.xx.gov.cn/art/2017/12/26/art_8801_1776060.html' title='标题3' target="_blank"></a>        <p>2017-12-26</p>    </li>    ]]></record>
<record><![CDATA[
    <li>        <a href='http://www.xx.gov.cn/art/2017/12/26/art_8801_1776059.html' title='标题4' target="_blank"></a>        <p>2017-12-26</p>    </li>    ]]></record>
<record><![CDATA[
    <li>        <a href='http://www.xx.gov.cn/art/2017/12/25/art_8801_1775473.html' title='标题5' target="_blank"></a>        <p>2017-12-25</p>    </li>    ]]></record>
<record><![CDATA[
    <li>        <a href='http://www.xx.gov.cn/art/2017/12/22/art_8801_1775476.html' title='标题6' target="_blank"></a>        <p>2017-12-22</p>    </li>    ]]></record>
<record><![CDATA[

方法正则表达式

string htmlcontext = “”;

Regex regex = new Regex(@"<a.*hrefs*=s*(?:""(?<url>[^""]*)""|'(?<url>[^']*)'|(?<url>[^>^s]+)).*>(?<title>[^<^>]*)<[^</a>]*/a>", RegexOptions.IgnoreCase);

for (Match m = regex.Match(htmlcontext); m.Success; m = m.NextMatch())
{
        string stringurl = m.Groups[1].Value.ToString();
        string stringtitle = m.Groups[2].Value.ToString();
}

输出结果：

http://www.xx.cn/art/2017/12/26/art_8801_1776064.html   标题1