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  • uva 1298

    半平面交的题;

    这个题目的亮点就是建模;

      1 #include<cstdio>
      2 #include<algorithm>
      3 #include<cmath>
      4 #define maxn 109
      5 #define eps 1e-6
      6 using namespace std;
      7 
      8 int dcmp(double x)
      9 {
     10     return fabs(x) < eps ? 0 : (x > 0 ? 1 : -1);
     11 }
     12 
     13 struct Point
     14 {
     15     double x;
     16     double y;
     17     Point(double x = 0, double y = 0):x(x), y(y) {}
     18 };
     19 typedef Point Vector;
     20 
     21 Vector operator + (Point A, Point B)
     22 {
     23     return Vector(A.x + B.x, A.y + B.y);
     24 }
     25 
     26 Vector operator - (Point A, Point B)
     27 {
     28     return Vector(A.x - B.x, A.y - B.y);
     29 }
     30 
     31 Vector operator * (Point A, double p)
     32 {
     33     return Vector(A.x * p, A.y * p);
     34 }
     35 
     36 Vector operator / (Point A, double p)
     37 {
     38     return Vector(A.x / p, A.y / p);
     39 }
     40 double dot(Point a,Point b)
     41 {
     42     return a.x*b.x+a.y*b.y;
     43 }
     44 double cross(Point a,Point b)
     45 {
     46     return a.x*b.y-a.y*b.x;
     47 }
     48 
     49 Vector nomal(Vector a)
     50 {
     51     double l=sqrt(dot(a,a));
     52     return Vector(-a.y/l,a.x/l);
     53 }
     54 
     55 struct line
     56 {
     57     Point p;
     58     Vector v;
     59     double ang;
     60     line() {}
     61     line(Point p,Vector v):p(p),v(v)
     62     {
     63         ang=atan2(v.y,v.x);
     64     }
     65     bool operator<(const line &t)const
     66     {
     67         return ang<t.ang;
     68     }
     69 };
     70 
     71 bool onleft(line l,Point p)
     72 {
     73     return (cross(l.v,p-l.p)>0);
     74 }
     75 
     76 Point getintersection(line a,line b)
     77 {
     78     Vector u=a.p-b.p;
     79     double t=cross(b.v,u)/cross(a.v,b.v);
     80     return a.p+a.v*t;
     81 }
     82 
     83 int halfplanintersection(line *l,int n,Point *poly)
     84 {
     85     sort(l,l+n);
     86     int first,last;
     87     Point *p=new Point[n];
     88     line *q=new line[n];
     89     q[first=last=0]=l[0];
     90     for(int i=1; i<n; i++)
     91     {
     92         while(first<last && !onleft(l[i],p[last-1]))last--;
     93         while(first<last && !onleft(l[i],p[first]))first++;
     94         q[++last]=l[i];
     95         if(fabs(cross(q[last].v,q[last-1].v))<eps)
     96         {
     97             last--;
     98             if(onleft(q[last],l[i].p))q[last]=l[i];
     99         }
    100         if(first<last)p[last-1]=getintersection(q[last-1],q[last]);
    101     }
    102     while(first<last && !onleft(q[first],p[last-1]))last--;
    103     if((last-first )<=1)return 0;
    104     p[last]=getintersection(q[last],q[first]);
    105     int m=0;
    106     for(int i=first; i<=last; i++)poly[m++]=p[i];
    107     return m;
    108 }
    109 
    110 Point poly[maxn];
    111 line l[maxn];
    112 double v[maxn],u[maxn],w[maxn];
    113 
    114 int main()
    115 {
    116     int n;
    117     while(scanf("%d",&n)!=EOF)
    118     {
    119         for(int i=0;i<n;i++)scanf("%lf%lf%lf",&v[i],&u[i],&w[i]);
    120         for(int i=0;i<n;i++)
    121         {
    122             double k=10000;
    123             bool flag=1;
    124             int cnt=0;
    125             for(int j=0;j<n;j++)
    126             {
    127                 if(i==j)continue;
    128                 if(v[j]>=v[i]&&u[j]>=u[i]&&w[j]>=w[i]){flag=0;break;}
    129                 if(v[j]<=v[i]&&w[j]<=u[i]&&w[j]<=w[i])continue;
    130                 double a=(k/v[j]-k/w[j])-(k/v[i]-k/w[i]);
    131                 double b=(k/u[j]-k/w[j])-(k/u[i]-k/w[i]);
    132                 double c=k/w[j]-k/w[i];
    133                 Point p;
    134                 Vector v(b,-a);
    135                 if(fabs(a)>fabs(b))p=Point(-c/a,0);
    136                 else p=Point(0,-c/b);
    137                 l[cnt++]=line(p,v);
    138             }
    139             if(flag)
    140             {
    141                 l[cnt++]=line(Point(0,0),Vector(0,-1));
    142                 l[cnt++]=line(Point(0,0),Vector(1,0));
    143                 l[cnt++]=line(Point(0,1),Vector(-1,1));
    144                 if(halfplanintersection(l,cnt,poly)==0)flag=0;
    145             }
    146             if(flag)puts("Yes");
    147             else puts("No");
    148         }
    149 
    150     }return 0;
    151 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yours1103/p/3409259.html
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