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  • uva 1475

    半平面交,二分;

    注意,题目的点是顺时针给出的;

      1 #include<cstdio>
      2 #include<algorithm>
      3 #include<cmath>
      4 #define maxn 50010
      5 #define eps 1e-6
      6 using namespace std;
      7 
      8 int dcmp(double x)
      9 {
     10     return fabs(x) < eps ? 0 : (x > 0 ? 1 : -1);
     11 }
     12 
     13 struct Point
     14 {
     15     double x;
     16     double y;
     17     Point(double x = 0, double y = 0):x(x), y(y) {}
     18 };
     19 typedef Point Vector;
     20 
     21 Vector operator + (Point A, Point B)
     22 {
     23     return Vector(A.x + B.x, A.y + B.y);
     24 }
     25 
     26 Vector operator - (Point A, Point B)
     27 {
     28     return Vector(A.x - B.x, A.y - B.y);
     29 }
     30 
     31 Vector operator * (Point A, double p)
     32 {
     33     return Vector(A.x * p, A.y * p);
     34 }
     35 
     36 Vector operator / (Point A, double p)
     37 {
     38     return Vector(A.x / p, A.y / p);
     39 }
     40 double dot(Point a,Point b)
     41 {
     42     return a.x*b.x+a.y*b.y;
     43 }
     44 double cross(Point a,Point b)
     45 {
     46     return a.x*b.y-a.y*b.x;
     47 }
     48 
     49 Vector nomal(Vector a)
     50 {
     51     double l=sqrt(dot(a,a));
     52     return Vector(-a.y/l,a.x/l);
     53 }
     54 
     55 struct line
     56 {
     57     Point p;
     58     Vector v;
     59     double ang;
     60     line() {}
     61     line(Point p,Vector v):p(p),v(v)
     62     {
     63         ang=atan2(v.y,v.x);
     64     }
     65     bool operator<(const line &t)const
     66     {
     67         return ang<t.ang;
     68     }
     69 };
     70 
     71 bool onleft(line l,Point p)
     72 {
     73     return (cross(l.v,p-l.p)>0);
     74 }
     75 
     76 Point getintersection(line a,line b)
     77 {
     78     Vector u=a.p-b.p;
     79     double t=cross(b.v,u)/cross(a.v,b.v);
     80     return a.p+a.v*t;
     81 }
     82 
     83 int halfplanintersection(line *l,int n,Point *poly)
     84 {
     85     sort(l,l+n);
     86     int first,last;
     87     Point *p=new Point[n];
     88     line *q=new line[n];
     89     q[first=last=0]=l[0];
     90     for(int i=1; i<n; i++)
     91     {
     92         while(first<last && !onleft(l[i],p[last-1]))last--;
     93         while(first<last && !onleft(l[i],p[first]))first++;
     94         q[++last]=l[i];
     95         if(fabs(cross(q[last].v,q[last-1].v))<eps)
     96         {
     97             last--;
     98             if(onleft(q[last],l[i].p))q[last]=l[i];
     99         }
    100         if(first<last)p[last-1]=getintersection(q[last-1],q[last]);
    101     }
    102     while(first<last && !onleft(q[first],p[last-1]))last--;
    103     if((last-first )<=1)return 0;
    104     p[last]=getintersection(q[last],q[first]);
    105     int m=0;
    106     for(int i=first; i<=last; i++)poly[m++]=p[i];
    107     return m;
    108 }
    109 
    110 Point p[maxn],poly[maxn],v[maxn];
    111 line l[maxn];
    112 
    113 int main()
    114 {
    115     int n;
    116     while(scanf("%d",&n)!=EOF)
    117     {
    118         for(int i=0;i<n;i++)scanf("%lf%lf",&p[i].x,&p[i].y);
    119         for(int i=1;i<=n/2;i++) swap(p[i],p[n-i]);
    120         int left=0,right=n-2;
    121         int ans;
    122         while(left<=right)
    123         {
    124             int mid=(left+right)>>1;
    125             for(int i=0;i<n;i++)
    126             {
    127                 v[i]=p[(i+mid+1)%n]-p[i];
    128                 l[i]=line(p[i],v[i]);
    129             }
    130             int m=halfplanintersection(l,n,poly);
    131             if(!m){ans=mid;right=mid-1;}
    132             else left=mid+1;
    133         }
    134         printf("%d
    ",ans);
    135     }
    136 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yours1103/p/3409300.html
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