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  • jquery处理json笔记

    1.
    var jsonStr = '{"a": 1, "b": "string", "c": [1, "11"]}';
    console.log(typeof(jsonStr)); // string
    var json = $.parseJSON(jsonStr);
    console.log(typeof(json)); // object
    console.log(json.c); // [1, "11"]
    
    2.
    <script>
    	$(function(){
    		var jsonStr = '{"id": 1, "name": "zhansan", "addr": [22, "33"]}';
    		var json = $.parseJSON(jsonStr);
    		var nd1 = "<td>"+json.id+"</td>";
    		var nd2 = "<td>"+json.name+"</td>";
    		var nd3 = "<td>"+json.addr[0]+"</td>";
    		var nd4 = "<td>"+json.addr[1]+"</td>";
    		var s = nd1+nd2+nd3+nd4;
    		$("tr:eq(0)").append(s);
    	});
    	
    </script>
    
    
    3.
    <script>
    	$(function(){
    		var jsonStr = '[{ "id" : 1 , "name" : "xiaoming"},' + 
    		'{"id" : 2 , "name" : "xiaohong"}, '+
    		'{"id" : 3 , "name" : "xiaowang"}]';		
    		
    		var json = $.parseJSON(jsonStr);
    		//alert(json.length);
    		
    		for(var i=0;i<json.length;i++){
    			$nd1 = "<td>"+json[i].id+"</td>" ;
    			$nd2 = "<td>"+json[i].name+"</td>" ;
    			$node = "<tr>"+$nd1 + $nd2+"</tr>";
    			$("table:eq(0)").append($node);
    		}
    	
    	});
    	
    </script>
    
    <table width="600" border="1">
          
        </table>
    

      

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  • 原文地址:https://www.cnblogs.com/yoyo198212/p/8848631.html
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