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  • 100. Same Tree

    题目:

    Given two binary trees, write a function to check if they are equal or not.

    Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

    链接: http://leetcode.com/problems/same-tree/

    题解:判断二叉树是否相同。 假如根节点都为空,则返回true; 根节点仅有一个为空,返回false; 根节点值相同,recursively比较两个子节点; 根节点值不同返回false。

    Time Complexity - O(n), Space Complexity - O(n)

    public class Solution {
        public boolean isSameTree(TreeNode p, TreeNode q) {
            if(p == null && q == null)
                return true;
            if(p == null || q == null)
                return false;
            if(p.val == q.val)
                return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
            else
                return false;
        }
    }

    二刷:

    先判断p和q为null的情况,接下来判断p和q的值是否相当,最后递归判断p和q左右子树是否相等。

    也可以用stack或者queue来做两棵树的traversal。看了一下discuss,有用两个stack的,也有用一个stack的,以后再继续研究。

    Java:

    Time Complexity - O(n), Space Complexity - O(n)

    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *     int val;
     *     TreeNode left;
     *     TreeNode right;
     *     TreeNode(int x) { val = x; }
     * }
     */
    public class Solution {
        public boolean isSameTree(TreeNode p, TreeNode q) {
            if (p == null || q == null) {
                return p == null && q == null;
            }
            if (p.val != q.val) {
                return false;
            } else {
                return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
            }
        }
    }

    三刷:

    要好好学一下coding style的line wrapping

    Java:

    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *     int val;
     *     TreeNode left;
     *     TreeNode right;
     *     TreeNode(int x) { val = x; }
     * }
     */
    public class Solution {
        public boolean isSameTree(TreeNode p, TreeNode q) {
            if (p == null || q == null) {
                return p == q;
            }
            return (p.val == q.val) 
                   ? isSameTree(p.left, q.left) && isSameTree(p.right, q.right) 
                   : false;
        }
    }

    Reference:

    http://yohanan.org/steve/projects/java-code-conventions/#SECTION00052000000000000000

    http://www.oracle.com/technetwork/articles/javase/codeconvtoc-136057.html

    http://www.oracle.com/technetwork/java/codeconventions-150003.pdf

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  • 原文地址:https://www.cnblogs.com/yrbbest/p/4437176.html
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