zoukankan      html  css  js  c++  java
  • java 两个数组合并

    需求:两个字符串合并(如果想去重复,参考下一篇--数组去重复及记录重复个数)
    //方法一 Arrays类
        String[] a = {"A","B","C"};
        String[] b = {"D","E"};
    // List<String> list = Arrays.asList(a); --OK
    // List<String> list = Arrays.asList("A","B","C"); --OK
    // list.add("F"); --UnsupportedOperationException
    // list.remove("A"); --UnsupportedOperationException
    // list.set(1,"javaee");--OK (因为是把数组转为集合,其本质还是数组,数组长度固定不变,但内容可以改变)
    // 结论:虽然可以把数组转为集合,但是集合长度不能改变
    List list
    = new ArrayList(Arrays.asList(a)); list.addAll(Arrays.asList(b)); String[] str = new String[list.size()]; list.toArray(str); for(int x=0;x<str.length;x++){ System.out.print(str[x] + " "); } //方法二 循环遍历 // 两个数组合并 String[] str1 = {"Hello","world","java"}; String[] str2 = {"Veriable","syntax","interator"}; String[] newStr = new String[str1.length+str2.length]; //newStr = str1;数组是引用类型 for(int x=0;x<str1.length;x++){ newStr[x] = str1[x]; } for(int y=0;y<str2.length;y++){ newStr[str1.length+y]=str2[y]; } for(int y=0;y<newStr.length;y++){ System.out.println(newStr[y] + " "); } // 方法三 String[] str1 = {"Hello","world","java"}; String[] str2 = {"Veriable","syntax","interator"}; int str1Length = str1.length; int str2length = str2.length; str1 = Arrays.copyOf(str1, str1Length+str2length);//数组扩容 System.arraycopy(str2, 0, str1, str1Length, str2length); System.out.println(Arrays.toString(str1));

     //

  • 相关阅读:
    sqlserver2005 新建批处理作业的步骤
    sql server 排除名字重复数据,获取最新的数据
    c#.net常用函数列表
    vs2008 ajax:AjaxPanel 页面无刷新操作
    解决asp.net中listbox的SelectedIndex的取值为1
    AjaxPro.Utility.RegisterTypeForAjax DropDownList三级联动
    我来了!
    《暗时间》读后感
    js判断是安卓手机还是ios
    angular各个版本下载
  • 原文地址:https://www.cnblogs.com/ysloong/p/6431127.html
Copyright © 2011-2022 走看看