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  • php根据二维数组中的某一元素相等,另一个元素相加

    二维数组:$taskData
     
    Array
    (
        [0] => Array
            (
                [area] => 1
                [winsFlag] => 7
                [count] => 3
            )
     
        [1] => Array
            (
                [area] => 1
                [winsFlag] => 3
                [count] => 2
            )
     
        [2] => Array
            (
                [area] => 1
                [winsFlag] => 5
                [count] => 2
            )
     
        [3] => Array
            (
                [area] => 2
                [winsFlag] => 6
                [count] => 2
            )
     
        [4] => Array
            (
                [area] => 2
                [winsFlag] => 3
                [count] => 2
            )
     
        [5] => Array
            (
                [area] => 3
                [winsFlag] => 7
                [count] => 3
            )
     
        [6] => Array
            (
                [area] => 3
                [winsFlag] => 1
                [count] => 1
            )
     
        [7] => Array
            (
                [area] => 4
                [winsFlag] => 2
                [count] => 1
            )
     
        [8] => Array
            (
                [area] => 4
                [winsFlag] => 2
                [count] => 1
            )
     
    )

    根据area相同将count相加

    $item=[];
    foreach($taskData as $k=>$v){
        if(!isset($item[$v['area']])){
            $item[$v['area']] = $v;
        }else{
            $item[$v['area']]['count'] += $v['count'];
        }
    }

    结果:得到一个新的数组 $item

    Array
    (
        [1] => Array
            (
                [area] => 1
                [winsFlag] => 7
                [count] => 7
            )
     
        [2] => Array
            (
                [area] => 2
                [winsFlag] => 6
                [count] => 4
            )
     
        [3] => Array
            (
                [area] => 3
                [winsFlag] => 7
                [count] => 4
            )
     
        [4] => Array
            (
                [area] => 4
                [winsFlag] => 2
                [count] => 2
            )
     
    )

    根据需求改变一下,把相同的值取出来,其余拼接一起

    $item=[];
    foreach($equityInfos as $k=>$v){
        if(!isset($item[$v['uid']])){
            $item[$v['uid']] = $v;
        }else{
            $item[$v['uid']]['product_id'] .= ','. $v['product_id'];
        }
    }
    

      上面说的是根据一个元素相等,假如要根据两个元素相等呢,下面就来解决

    Array
    (
        [0] => Array
            (
                [send_detail_id] => 65379
                [amount] => 1
                [sn] => MB12-69-181
            ),
        [1] => Array
            (
                [send_detail_id] => 65380
                [amount] => 2
                [sn] =>MB12-69-181
            ),
        [2] => Array
            (
                [send_detail_id] =>65380
                [amount] => 1
                [sn] => MB12-69-181
            ),
        [3] => Array
            (
                [send_detail_id] => 65382
                [amount] => 1
                [sn] => SA12-64-180N2001
            )
    )
    如果两个字段send_detail_id和sn相同才合并求和,结果应该是这种
    Array
    (
        [0] => Array
            (
                [send_detail_id] => 65379
                [amount] => 1
                [sn] => MB12-69-181
            ),
        [1] => Array
            (
                [send_detail_id] => 65380
                [amount] => 3  //和后面的相加了,第一个就不能和他相加
                [sn] =>MB12-69-181
            ),
      
        [3] => Array
            (
                [send_detail_id] => 65382
                [amount] => 1
                [sn] => SA12-64-180N2001
            )
    )
    其实很简单
    foreach($arr as $v){
        if(!isset($ret[$v['send_detail_id'].'_'.$v['sn']])){
            $ret[$v['send_detail_id'].'_'.$v['sn']] = $v;
        }else{
            $ret[$v['send_detail_id'].'_'.$v['sn']]['amount'] += $v['amount'];
        }
    }
    print_r(array_values($ret));
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  • 原文地址:https://www.cnblogs.com/yszr/p/11461757.html
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