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  • 几何多边形面积交模板

    求连个多边形相交的面积

    #include<bits/stdc++.h>  
    using namespace std;  
      
    const int maxn=555;  
    const int maxisn=10;  
    const double eps=1e-8;  
    const double pi=acos(-1.0);  
      
    int dcmp(double x){  
        if(x>eps) return 1;  
        return x<-eps ? -1 : 0;  
    }  
    inline double Sqr(double x){  
        return x*x;  
    }  
    struct Point{  
        double x,y;  
        Point(){x=y=0;}  
        Point(double x,double y):x(x),y(y){};  
        friend Point operator + (const Point &a,const Point &b) {  
            return Point(a.x+b.x,a.y+b.y);  
        }  
        friend Point operator - (const Point &a,const Point &b) {  
            return Point(a.x-b.x,a.y-b.y);  
        }  
        friend bool operator == (const Point &a,const Point &b) {  
            return dcmp(a.x-b.x)==0&&dcmp(a.y-b.y)==0;  
        }  
        friend Point operator * (const Point &a,const double &b) {  
            return Point(a.x*b,a.y*b);  
        }  
        friend Point operator * (const double &a,const Point &b) {  
            return Point(a*b.x,a*b.y);  
        }  
        friend Point operator / (const Point &a,const double &b) {  
            return Point(a.x/b,a.y/b);  
        }  
        friend bool operator < (const Point &a, const Point &b) {  
            return a.x < b.x || (a.x == b.x && a.y < b.y);  
        }  
        inline double dot(const Point &b)const{  
            return x*b.x+y*b.y;  
        }  
        inline double cross(const Point &b,const Point &c)const{  
            return (b.x-x)*(c.y-y)-(c.x-x)*(b.y-y);  
        }  
      
    };  
      
    Point LineCross(const Point &a,const Point &b,const Point &c,const Point &d){  
        double u=a.cross(b,c),v=b.cross(a,d);  
        return Point((c.x*v+d.x*u)/(u+v),(c.y*v+d.y*u)/(u+v));  
    }  
    double PolygonArea(Point p[],int n){  
         if(n<3) return 0.0;  
         double s=p[0].y*(p[n-1].x-p[1].x);  
         p[n]=p[0];  
         for(int i=1;i<n;i++){  
            s+=p[i].y*(p[i-1].x-p[i+1].x);  
         }  
         return fabs(s*0.5);  
    }  
    double CPIA(Point a[],Point b[],int na,int nb){  
        Point p[maxisn],temp[maxisn];  
        int i,j,tn,sflag,eflag;  
        a[na]=a[0],b[nb]=b[0];  
        memcpy(p,b,sizeof(Point)*(nb+1));  
        for(i=0;i<na&&nb>2;++i){  
            sflag=dcmp(a[i].cross(a[i+1],p[0]));  
            for(j=tn=0;j<nb;++j,sflag=eflag){  
                if(sflag>=0) temp[tn++]=p[j];  
                eflag=dcmp(a[i].cross(a[i+1],p[j+1]));  
                if((sflag^eflag)==-2)  
                    temp[tn++]=LineCross(a[i],a[i+1],p[j],p[j+1]);  
            }  
            memcpy(p,temp,sizeof(Point)*tn);  
            nb=tn,p[nb]=p[0];  
        }  
        if(nb<3) return 0.0;  
        return PolygonArea(p,nb);  
    }  
    double SPIA(Point a[],Point b[],int na,int nb){  
        int i,j;  
        Point t1[4],t2[4];  
        double res=0.0,if_clock_t1,if_clock_t2;  
        a[na]=t1[0]=a[0];  
        b[nb]=t2[0]=b[0];  
        for(i=2;i<na;i++){  
            t1[1]=a[i-1],t1[2]=a[i];  
            if_clock_t1=dcmp(t1[0].cross(t1[1],t1[2]));  
            if(if_clock_t1<0) swap(t1[1],t1[2]);  
            for(j=2;j<nb;j++){  
                t2[1]=b[j-1],t2[2]=b[j];  
                if_clock_t2=dcmp(t2[0].cross(t2[1],t2[2]));  
                if(if_clock_t2<0) swap(t2[1],t2[2]);  
                res+=CPIA(t1,t2,3,3)*if_clock_t1*if_clock_t2;  
            }  
        }  
        return res;//面积交  
        //return PolygonArea(a,na)+PolygonArea(b,nb)-res;//面积并  
    }  
    Point a[4],b[5];  
      
    int main()  
    {  
        double x1,x2,x3,x4,y1,y2,y3,y4;  
        while(scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2)!=EOF)  
        {  
           scanf("%lf%lf%lf%lf",&x3,&y3,&x4,&y4);  
           a[0]=Point(x1,y1);  
           a[1]=Point(x2,y1);  
           a[2]=Point(x1,y2);  
           b[0]=Point(x3,y3);  
           b[1]=Point(x3,y4);  
           b[2]=Point(x4,y4);  
           b[3]=Point(x4,y3);  
           printf("%.8lf
    ",fabs(SPIA(a,b,3,4)));  
        }  
    }  
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  • 原文地址:https://www.cnblogs.com/yuanbo123/p/6734283.html
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