The Triangle
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 43809 | Accepted: 26430 |
Description
7
3 8
8 1 0
2 7 4 4
4 5 2 6 5
(Figure 1)
Input
Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.
Output
Your program is to write to standard output. The highest sum is written as an integer.
Sample Input
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5
Sample Output
30
Source
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
1 #include<cstdio> 2 #include<iostream> 3 #define N 100+10 4 5 using namespace std; 6 7 int a[N][N],n; 8 9 int main() 10 { 11 scanf("%d",&n); 12 for(int i=1;i<=n;i++) 13 for(int j=1;j<=i;j++) //数字三角形的读入 14 scanf("%d",&a[i][j]); 15 for(int i=n-1;i>=1;i--) 16 for(int j=1;j<=i;j++) //从下向上每一个点都可以加上他两个孩子之中较大的那个,当加到a[1][1]是,就是最大的值 17 //因为不需要输出路径,所以可以直接在原数组上修改 18 a[i][j]+=max(a[i+1][j],a[i+1][j+1]); 19 printf("%d",a[1][1]); 20 return 0; 21 } 22