zoukankan      html  css  js  c++  java
  • Codeforces 71A

    题目: A. Way Too Long Words

    time limit per test: 1 second
    memory limit per test: 256 megabytes
    input: standard input
    output:standard output

    Sometimes some words like “localization” or “internationalization” are so long that writing them many times in one text is quite tiresome.

    Let’s consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.

    This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn’t contain any leading zeroes.

    Thus, “localization” will be spelt as “l10n”, and "internationalization» will be spelt as “i18n”.

    You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.

    Input

    The first line contains an integer n (1 ≤ n ≤ 100). Each of the following n lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.

    Output

    Print n lines. The i-th line should contain the result of replacing of the i-th word from the input data.

    Examples

    input
    4
    word
    localization
    internationalization
    pneumonoultramicroscopicsilicovolcanoconiosis
    output
    word
    l10n
    i18n
    p43s

    思路:

    用string接收字符串,如果该字符串长度小于等于10,则原样输出;否则输出首字符+(length-2)+尾字符;

    代码:

    #include<iostream>
    using namespace std;
    int main(){
    	int n;
    	cin>>n;
    	for(int i=0;i<n;i++){
    		string s;
    		cin>>s;
    		if(s.length()<=10) printf("%s
    ",s.c_str());
    		else printf("%c%d%c
    ",s[0],s.length()-2,s[s.length()-1]);
    	}
    	return 0;
    }
    
  • 相关阅读:
    ZYNQ. Interrupt(1)Private Timer
    RaspberryPi.1.开机与远程桌面
    ZYNQ. DMA基本用法
    ZYNQ. LwIP.PHY.KSZ9031RNX
    Verilog笔记.三段式状态机
    c语言.函数指针数组
    c语言学习笔记.链表.
    D3D基本框架:即D3D头文件分类
    win32窗口:关于鼠标定位位置偏移问题的原因及解决方法
    <转>C++基础知识: 引用
  • 原文地址:https://www.cnblogs.com/yuhan-blog/p/12308986.html
Copyright © 2011-2022 走看看