zoukankan      html  css  js  c++  java
  • 2001. Counting Sheep

     
    After a long night of coding, Charles Pearson Peterson is having trouble sleeping. This is not only because he is still thinking about the problem he is working on but also due to drinking too much java during the wee hours. This happens frequently, so Charles has developed a routine to count sheep. Not the animal, but the word. Specifically, he thinks of a list of words, many of which are close in spelling to "sheep", and then counts how many actually are the word "sheep". Charles is always careful to be case-sensitive in his matching, so "Sheep" is not a match. You are to write a program that helps Charles count "sheep".

    Input

    Input will consist of multiple problem instances. The first line will consist of a single positive integer n ≤ 20, which is the number of problem instances. The input for each problem instance will be on two lines. The first line will consist of a positive integer m ≤ 10 and the second line will consist of m words, separated by a single space and each containing no more than 10 characters.

    Output

    For each problem instance, you are to produce one line of output in the format:

    Case i: This list contains n sheep.

    The value of i is the number of the problem instance (we assume we start numbering at 1) and n is the number of times the word "sheep" appears in the list of words for that problem instance. Two successive lines should be separated by a single blank line, but do not output any trailing blank line.

    Sample Input

    4
    5
    shep sheeps sheep ship Sheep
    7
    sheep sheep SHEEP sheep shepe shemp seep
    10
    sheep sheep sheep sheep sheep sheep sheep sheep sheep sheep
    4
    shape buffalo ram goat
    

    Sample Output

    Case 1: This list contains 1 sheep.
    
    Case 2: This list contains 3 sheep.
    
    Case 3: This list contains 10 sheep.
    
    Case 4: This list contains 0 sheep.
    



    Source: East Central North America 2000 Practice

     1 #include <stdio.h>
     2 #include <string.h>
     3 
     4 char str[150];
     5 char sheep[6] = "sheep";
     6 
     7 int main () 
     8 { 
     9     int m,n;
    10     int numCount;
    11     scanf("%d",&m);
    12     int i=0;
    13     while(i<m)
    14     {
    15         numCount=0;
    16         scanf("%d",&n);
    17         getchar();
    18         gets(str);
    19         char *ptr = str;
    20         while(n--)
    21         {
    22             int j;
    23             if((memcmp(ptr,sheep,5) == 0)&&((*(ptr+5) == ' ')||(*(ptr+5) == '')))
    24             {
    25                 numCount++;
    26                 ptr+=6;
    27             }
    28             else
    29             {
    30                 for(j=0;j<11;j++)
    31                 {
    32                     if(*ptr++ != ' ')
    33                         continue;
    34                     break;
    35                 }
    36             }              
    37         }
    38         printf("Case %d: This list contains %d sheep.
    ",++i,numCount);
    39         if(i<m)
    40             printf("
    ");
    41         numCount = 0; 
    42     }
    43     return 0;
    44 }
  • 相关阅读:
    安装oracle客户端后,怎样设置电脑的环境变量?
    KETTLE、spoon使用
    软件环境常识 --dev sit uat
    使用 CAS 在 Tomcat 中实现单点登录 http://www.ibm.com/developerworks/cn/opensource/os-cn-cas/
    oracle数据库的完整性约束规则详解
    Oracle创建表语句(Create table)语法详解及示例
    Oracle TO_DATE 日期格式
    L/SQL Developer 和 instantclient客户端安装配置
    mysql里的序列应用详解
    .net core 使用 textSharp生成pdf
  • 原文地址:https://www.cnblogs.com/yushuo1990/p/4340980.html
Copyright © 2011-2022 走看看