想了辣么多 貌似就一个条件
#include<bits/stdc++.h> using namespace std; int flag=0;int main(){int t,n,kase=1;scanf("%d",&t);while(t--){flag=0;scanf("%d",&n);for(int i=0;i<n;i++){int r,e,l;scanf("%d%d%d",&r,&e,&l);if(e < r) flag=1; }printf("Case #%d: ",kase++);if(flag) printf("NO "); else printf("YES ");}return 0;}