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  • System.arraycopy 怎么使用的?

    前言:看 ArrayList 的源码,发现 remove 方法主要依赖了 System.arraycopy() 方法实现的。所以需要了解一下这个方法如何使用。转载请注明出处:https://www.cnblogs.com/yuxiaole/p/9951819.html

    源码

    带注释的源码:

        /**
         * Copies an array from the specified source array, beginning at the
         * specified position, to the specified position of the destination array.
         * A subsequence of array components are copied from the source
         * array referenced by <code>src</code> to the destination array
         * referenced by <code>dest</code>. The number of components copied is
         * equal to the <code>length</code> argument. The components at
         * positions <code>srcPos</code> through
         * <code>srcPos+length-1</code> in the source array are copied into
         * positions <code>destPos</code> through
         * <code>destPos+length-1</code>, respectively, of the destination
         * array.
         * <p>
         * If the <code>src</code> and <code>dest</code> arguments refer to the
         * same array object, then the copying is performed as if the
         * components at positions <code>srcPos</code> through
         * <code>srcPos+length-1</code> were first copied to a temporary
         * array with <code>length</code> components and then the contents of
         * the temporary array were copied into positions
         * <code>destPos</code> through <code>destPos+length-1</code> of the
         * destination array.
         * <p>
         * If <code>dest</code> is <code>null</code>, then a
         * <code>NullPointerException</code> is thrown.
         * <p>
         * If <code>src</code> is <code>null</code>, then a
         * <code>NullPointerException</code> is thrown and the destination
         * array is not modified.
         * <p>
         * Otherwise, if any of the following is true, an
         * <code>ArrayStoreException</code> is thrown and the destination is
         * not modified:
         * <ul>
         * <li>The <code>src</code> argument refers to an object that is not an
         *     array.
         * <li>The <code>dest</code> argument refers to an object that is not an
         *     array.
         * <li>The <code>src</code> argument and <code>dest</code> argument refer
         *     to arrays whose component types are different primitive types.
         * <li>The <code>src</code> argument refers to an array with a primitive
         *    component type and the <code>dest</code> argument refers to an array
         *     with a reference component type.
         * <li>The <code>src</code> argument refers to an array with a reference
         *    component type and the <code>dest</code> argument refers to an array
         *     with a primitive component type.
         * <
    View Code

    不带注释的源码:

        public static native void arraycopy(Object src,  int  srcPos,
                                            Object dest, int destPos,
                                            int length);

    参数解释:  

      src: 源数组; 

      srcPos: 源数组要复制的起始位置;

       dest: 目的数组; 

      destPos: 目的数组放置的起始位置; 

      length: 复制的长度。

    从源码注释中就可以看出

      1、拷贝过程:将 src 数组的下标为 srcPos 到 srcPos + length - 1 拷贝到 dest 数组下标为 destPos 到 destPos + length- 1 的位置。

      2、这个也支持 src 和 dest 为同一个数组,这时会将原数组拷贝到临时数组里,然后再将临时数组的数据拷贝到目标数组。

      3、如果 src 或者 dest 为 null ,则会抛空指针异常。

      4、如果 src 或者 dest 不是数组,则会抛出 ArrayStoreException。

      5、src,dest 不是同类型或者可以进行转换的数组,则会抛出 ArrayStoreException。

      6、如果 srcPos + length > length或者 destPos + lenght > length,则会抛出 IndexOutOfBoundsException。  

    测试:

    转载请注明出处:https://www.cnblogs.com/yuxiaole/p/9951819.html

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  • 原文地址:https://www.cnblogs.com/yuxiaole/p/9951819.html
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