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  • 洛谷-P2871 [USACO07DEC]Charm Bracelet S

    洛谷-P2871 [USACO07DEC]Charm Bracelet S

    原题链接:


    题目描述

    Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

    Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

    有N件物品和一个容量为V的背包。第i件物品的重量是c[i],价值是w[i]。求解将哪些物品装入背包可使这些物品的重量总和不超过背包容量,且价值总和最大。

    输入格式

    * Line 1: Two space-separated integers: N and M

    * Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di

    第一行:物品个数N和背包大小M

    第二行至第N+1行:第i个物品的重量C[i]和价值W[i]

    输出格式

    * Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

    输出一行最大价值。

    输入输出样例

    输入 #1

    4 6
    1 4
    2 6
    3 12
    2 7
    

    输出 #1

    23
    

    C++代码

    #include <iostream>
    using namespace std;
    
    int f[12885];
    
    int main() {
        int n, m;
        cin >> n >> m;
        int c[n], w[n];
        for (int i=0; i<n; ++i)
            cin >> c[i] >> w[i];
        for (int i=0; i<n; ++i)
            for (int j=m; j>=c[i]; --j)
                f[j] = max(f[j], f[j-c[i]]+w[i]);
        cout << f[m] << endl;
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/yuzec/p/14308308.html
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