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  • UVA 401 Palindromes

    这道题憋了好久,题很简单,错在了输出格式:每行之间有空格 judge后wrong answer,值得注意。

    #include<stdio.h>
    #include<string.h>
    char s[25];
    int palin(char* s)
    {
    int len = strlen(s);
    for(int i = 0; i < len/2; i ++)
    if(s[i] != s[len-1-i])return 0;
    return 1;
    }
    int mirr(char* s)
    {
    char s1[40]="ABCDEHIJKLMNOPQRSTUVWXYZ123456789";
    char s2[40]="A 3HIL JM O 2TUVWXY51SE4Z 8 ";
    int len = strlen(s);
    if((len==1)&&(s[0] != s2[strchr(s1,s[0])-s1])) return 0;
    for(int i = 0; i <= len/2; i ++)
    {
    if(!strchr(s1,s[i])) return 0;
    else
    {
    int p = strchr(s1,s[i]) - s1;
    if(s[len-i-1] != s2[p]) return 0;
    }
    }
    return 1;
    }
    int main()
    {
    while(scanf("%s",s) == 1)
    {
    //printf("p=%d m=%d\n",palin(s),mirr(s));
    if(palin(s) && mirr(s))
    printf("%s -- is a mirrored palindrome.\n",s);
    if(palin(s) && !mirr(s))
    printf("%s -- is a regular palindrome.\n",s);
    if(!palin(s) && mirr(s))
    printf("%s -- is a mirrored string.\n",s);
    if(!palin(s) && !mirr(s))
    printf("%s -- is not a palindrome.\n",s);
    printf("\n");
    }
    return 0;
    }



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  • 原文地址:https://www.cnblogs.com/yuzhaoxin/p/2288197.html
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