cdoj 1070 秋实大哥打游戏 带权并查集

题目链接:

http://acm.uestc.edu.cn/#/problem/show/1070

题意:

题解:

带权并查集
每次往上更新的时候，顺便把边权更新了就好
记住得路径压缩

代码:

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define MS(a) memset(a,0,sizeof(a))
#define MP make_pair
#define PB push_back
const int INF = 0x3f3f3f3f;
const ll INFLL = 0x3f3f3f3f3f3f3f3fLL;
inline ll read(){
    ll x=0,f=1;char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
    return x*f;
}
//////////////////////////////////////////////////////////////////////////
const int maxn = 1e5+10;

int fa[maxn];
ll w[maxn];

int find(int x){
    if(fa[x] == x) return x;

    find(fa[x]);
    w[x] += w[fa[x]];
    fa[x] = find(fa[x]);
    return fa[x];
}

void Union(int v,int u){
    int t1 = find(v), t2 = find(u);
    if(t1 == t2) return ;
    fa[v] = t2;
    w[v] = abs(u-v) % 1000 + w[u];
}

int main(){
    int n=read();
    for(int i=0; i<=n; i++){
        fa[i] = i;
        w[i] = 0;
    }
    char op;
    while(scanf(" %c",&op) && op!='O'){
        if(op=='I'){
            int v,u; scanf("%d%d",&v,&u);
            Union(v,u);
        }else{
            int x=read();
            find(x);
            printf("%lld
",w[x]);
        }
    }

    return 0;
}