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  • iOS在地图上WGS84、GCJ-02、BD-09互转解决方案

              该项目的最新进展包括地图共享模块,android同事集团开始,使用百度地图sdk,我开始回,运用iOS SDK的mapkit做,之后,问题是,用纬度和经度坐标iOS端和Android端出现了比較大偏差。查了下资料苹果地图在大陆的数据源是高德的,查了下高德採用GCJ-02, 百度map sdk 採用的是BD-09。仅仅好写了个类在发送和接收时做好转换,稍微蛋疼。Github上有人写了一个现成的转换类,能够參考參考传送门 。其主要代码见下:

    头文件:

    #import <Foundation/Foundation.h>
    #import <CoreLocation/CoreLocation.h>
    @interface JZLocationConverter : NSObject
    
    /**
     *	@brief	世界标准地理坐标(WGS-84) 转换成 中国国測局地理坐标(GCJ-02)<火星坐标>
     *
     *  ####仅仅在中国大陆的范围的坐标有效,以外直接返回世界标准坐标
     *
     *	@param 	location 	世界标准地理坐标(WGS-84)
     *
     *	@return	中国国測局地理坐标(GCJ-02)<火星坐标>
     */
    + (CLLocationCoordinate2D)wgs84ToGcj02:(CLLocationCoordinate2D)location;
    
    
    /**
     *	@brief	中国国測局地理坐标(GCJ-02) 转换成 世界标准地理坐标(WGS-84)
     *
     *  ####此接口有1-2米左右的误差,须要精确定位情景慎用
     *
     *	@param 	location 	中国国測局地理坐标(GCJ-02)
     *
     *	@return	世界标准地理坐标(WGS-84)
     */
    + (CLLocationCoordinate2D)gcj02ToWgs84:(CLLocationCoordinate2D)location;
    
    
    /**
     *	@brief	世界标准地理坐标(WGS-84) 转换成 百度地理坐标(BD-09)
     *
     *	@param 	location 	世界标准地理坐标(WGS-84)
     *
     *	@return	百度地理坐标(BD-09)
     */
    + (CLLocationCoordinate2D)wgs84ToBd09:(CLLocationCoordinate2D)location;
    
    
    /**
     *	@brief	中国国測局地理坐标(GCJ-02)<火星坐标> 转换成 百度地理坐标(BD-09)
     *
     *	@param 	location 	中国国測局地理坐标(GCJ-02)<火星坐标>
     *
     *	@return	百度地理坐标(BD-09)
     */
    + (CLLocationCoordinate2D)gcj02ToBd09:(CLLocationCoordinate2D)location;
    
    
    /**
     *	@brief	百度地理坐标(BD-09) 转换成 中国国測局地理坐标(GCJ-02)<火星坐标>
     *
     *	@param 	location 	百度地理坐标(BD-09)
     *
     *	@return	中国国測局地理坐标(GCJ-02)<火星坐标>
     */
    + (CLLocationCoordinate2D)bd09ToGcj02:(CLLocationCoordinate2D)location;
    
    
    /**
     *	@brief	百度地理坐标(BD-09) 转换成 世界标准地理坐标(WGS-84)
     *
     *  ####此接口有1-2米左右的误差,须要精确定位情景慎用
     *
     *	@param 	location 	百度地理坐标(BD-09)
     *
     *	@return	世界标准地理坐标(WGS-84)
     */
    + (CLLocationCoordinate2D)bd09ToWgs84:(CLLocationCoordinate2D)location;
    
    
    @end

    实现文件

    #import "JZLocationConverter.h"
    #import <CoreLocation/CoreLocation.h>
    #define LAT_OFFSET_0(x,y) -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(fabs(x))
    #define LAT_OFFSET_1 (20.0 * sin(6.0 * x * M_PI) + 20.0 * sin(2.0 * x * M_PI)) * 2.0 / 3.0
    #define LAT_OFFSET_2 (20.0 * sin(y * M_PI) + 40.0 * sin(y / 3.0 * M_PI)) * 2.0 / 3.0
    #define LAT_OFFSET_3 (160.0 * sin(y / 12.0 * M_PI) + 320 * sin(y * M_PI / 30.0)) * 2.0 / 3.0
    
    #define LON_OFFSET_0(x,y) 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(fabs(x))
    #define LON_OFFSET_1 (20.0 * sin(6.0 * x * M_PI) + 20.0 * sin(2.0 * x * M_PI)) * 2.0 / 3.0
    #define LON_OFFSET_2 (20.0 * sin(x * M_PI) + 40.0 * sin(x / 3.0 * M_PI)) * 2.0 / 3.0
    #define LON_OFFSET_3 (150.0 * sin(x / 12.0 * M_PI) + 300.0 * sin(x / 30.0 * M_PI)) * 2.0 / 3.0
    
    #define RANGE_LON_MAX 137.8347
    #define RANGE_LON_MIN 72.004
    #define RANGE_LAT_MAX 55.8271
    #define RANGE_LAT_MIN 0.8293
    // jzA = 6378245.0, 1/f = 298.3
    // b = a * (1 - f)
    // ee = (a^2 - b^2) / a^2;
    #define jzA 6378245.0
    #define jzEE 0.00669342162296594323
    
    
    
    @implementation JZLocationConverter
    
    + (double)transformLat:(double)x bdLon:(double)y
    {
        double ret = LAT_OFFSET_0(x, y);
        ret += LAT_OFFSET_1;
        ret += LAT_OFFSET_2;
        ret += LAT_OFFSET_3;
        return ret;
    }
    
    + (double)transformLon:(double)x bdLon:(double)y
    {
        double ret = LON_OFFSET_0(x, y);
        ret += LON_OFFSET_1;
        ret += LON_OFFSET_2;
        ret += LON_OFFSET_3;
        return ret;
    }
    
    + (BOOL)outOfChina:(double)lat bdLon:(double)lon
    {
        if (lon < RANGE_LON_MIN || lon > RANGE_LON_MAX)
            return true;
        if (lat < RANGE_LAT_MIN || lat > RANGE_LAT_MAX)
            return true;
        return false;
    }
    
    + (CLLocationCoordinate2D)gcj02Encrypt:(double)ggLat bdLon:(double)ggLon
    {
        CLLocationCoordinate2D resPoint;
        double mgLat;
        double mgLon;
        if ([self outOfChina:ggLat bdLon:ggLon]) {
            resPoint.latitude = ggLat;
            resPoint.longitude = ggLon;
            return resPoint;
        }
        double dLat = [self transformLat:(ggLon - 105.0)bdLon:(ggLat - 35.0)];
        double dLon = [self transformLon:(ggLon - 105.0) bdLon:(ggLat - 35.0)];
        double radLat = ggLat / 180.0 * M_PI;
        double magic = sin(radLat);
        magic = 1 - jzEE * magic * magic;
        double sqrtMagic = sqrt(magic);
        dLat = (dLat * 180.0) / ((jzA * (1 - jzEE)) / (magic * sqrtMagic) * M_PI);
        dLon = (dLon * 180.0) / (jzA / sqrtMagic * cos(radLat) * M_PI);
        mgLat = ggLat + dLat;
        mgLon = ggLon + dLon;
        
        resPoint.latitude = mgLat;
        resPoint.longitude = mgLon;
        return resPoint;
    }
    
    + (CLLocationCoordinate2D)gcj02Decrypt:(double)gjLat gjLon:(double)gjLon {
        CLLocationCoordinate2D  gPt = [self gcj02Encrypt:gjLat bdLon:gjLon];
        double dLon = gPt.longitude - gjLon;
        double dLat = gPt.latitude - gjLat;
        CLLocationCoordinate2D pt;
        pt.latitude = gjLat - dLat;
        pt.longitude = gjLon - dLon;
        return pt;
    }
    
    + (CLLocationCoordinate2D)bd09Decrypt:(double)bdLat bdLon:(double)bdLon
    {
        CLLocationCoordinate2D gcjPt;
        double x = bdLon - 0.0065, y = bdLat - 0.006;
        double z = sqrt(x * x + y * y) - 0.00002 * sin(y * M_PI);
        double theta = atan2(y, x) - 0.000003 * cos(x * M_PI);
        gcjPt.longitude = z * cos(theta);
        gcjPt.latitude = z * sin(theta);
        return gcjPt;
    }
    
    +(CLLocationCoordinate2D)bd09Encrypt:(double)ggLat bdLon:(double)ggLon
    {
        CLLocationCoordinate2D bdPt;
        double x = ggLon, y = ggLat;
        double z = sqrt(x * x + y * y) + 0.00002 * sin(y * M_PI);
        double theta = atan2(y, x) + 0.000003 * cos(x * M_PI);
        bdPt.longitude = z * cos(theta) + 0.0065;
        bdPt.latitude = z * sin(theta) + 0.006;
        return bdPt;
    }
    
    
    + (CLLocationCoordinate2D)wgs84ToGcj02:(CLLocationCoordinate2D)location
    {
        return [self gcj02Encrypt:location.latitude bdLon:location.longitude];
    }
    
    + (CLLocationCoordinate2D)gcj02ToWgs84:(CLLocationCoordinate2D)location
    {
        return [self gcj02Decrypt:location.latitude gjLon:location.longitude];
    }
    
    
    + (CLLocationCoordinate2D)wgs84ToBd09:(CLLocationCoordinate2D)location
    {
        CLLocationCoordinate2D gcj02Pt = [self gcj02Encrypt:location.latitude
                                                      bdLon:location.longitude];
        return [self bd09Encrypt:gcj02Pt.latitude bdLon:gcj02Pt.longitude] ;
    }
    
    + (CLLocationCoordinate2D)gcj02ToBd09:(CLLocationCoordinate2D)location
    {
        return  [self bd09Encrypt:location.latitude bdLon:location.longitude];
    }
    
    + (CLLocationCoordinate2D)bd09ToGcj02:(CLLocationCoordinate2D)location
    {
        return [self bd09Decrypt:location.latitude bdLon:location.longitude];
    }
    
    + (CLLocationCoordinate2D)bd09ToWgs84:(CLLocationCoordinate2D)location
    {
        CLLocationCoordinate2D gcj02 = [self bd09ToGcj02:location];
        return [self gcj02Decrypt:gcj02.latitude gjLon:gcj02.longitude];
    }
    
    @end
    

    測试用例:

        CLLocationCoordinate2D gcj02 = CLLocationCoordinate2DMake(114.21892734521,29.575429778924);
        CLLocationCoordinate2D bd09 = [JZLocationConverter gcj02ToBd09:gcj02];
        NSLog(@"%f,%f", bd09.latitude, bd09.longitude); 
    
        // http://developer.baidu.com/map/index.php?title=webapi/guide/changeposition
        // JZLocationConverter 測试数据: 114.21892734521,29.575429778924  ; 转化结果: 114.224960,29.581853
        // 百度api  測试数据: 114.21892734521,29.575429778924  ; 百度api转换结果: 114.22539195429,29.581585367458

             整体来说,存在一点偏差,但跟处理前的效果比一下。相对能够接受了些。


    參考:

    http://blog.csdn.net/jiajiayouba/article/details/25140967

    http://developer.baidu.com/map/index.php?

    title=webapi/guide/changeposition

    http://blog.csdn.net/winnyrain/article/details/22233559

    http://www.kuaifenxiang.net/article/17

    http://blog.csdn.net/coolypf/article/details/8569813

    http://www.cppblog.com/socketref/archive/2011/06/29/149713.html

    版权声明:本文博主原创文章,博客,未经同意不得转载。

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  • 原文地址:https://www.cnblogs.com/yxwkf/p/4792462.html
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