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  • 月球美容计划之图的储存结构汇总

    SJ图论非常流弊,为了省赛队里知识尽量广,我就直接把图continue,如今回想起来丫的全忘了,从头開始吧。

    先写写图的存储,再写写最小生成树和最短路的几个经典算法,月球美容计划就能够结束了。0 0。拖了好久,还有非常多内容要写。- -

    这次总结了邻接矩阵,邻接表。十字链表。邻接多重表,边集数组,这5种经常使用的图的储存结构,或许能当模板用吧。

     

    邻接矩阵

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //邻接矩阵
    int G[100][100];
    int add1 (int i,int j,int w)
    {
        G[i][j] = w;
    	return 0;
    }
    
    int main()
    {
        int i,n;
        
        //建图
    	scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            add1 (a,b,w);
            //无向图加上
            add1 (b,a,w);
        }
        return 0;
    }


    邻接表

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //邻接表
    
    struct dot
    {
        int d;
        int w;
        struct dot *next;
    };
    
    struct hed
    {
        int v;
        struct dot *next;
    }head[100];
    
    int add2(int i,int j,int w)
    {
        struct dot * p;
        struct dot * t = new dot;
    
        t->d = j;
        t->w = w;
        t->next = NULL;
    
        if (head[i].next == NULL)
        {
            head[i].next = t;
            return 0;
        }
    
        p = head[i].next;
    
        while (p->next != NULL)
            p = p->next;
    
        p->next = t;
    
        return 0;
    }
    
    int main()
    {
        int i,n;
    	
    	memset (head,0,sizeof (head));
        //建图
        scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            add2 (a,b,w);
            //无向图加上
            add2 (b,a,w);
        }
        return 0;
    }


    十字链表(有向图好用)

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //十字链表
    
    struct dot
    {
        int d;
        int w;
        struct dot *next;
    };
    
    struct hed
    {
        int v;
        struct dot *to;
        struct dot *next;
    }head[100];
    
    int add3(int i,int j,int w)
    {
        struct dot * p;
        struct dot * t = new dot;
    
        t->d = j;
        t->w = w;
        t->next = NULL;
    
        //正邻接表构建
        if (head[i].next == NULL)
        {
            head[i].next = t;
        }else
        {
            p = head[i].next;
    
            while (p->next != NULL)
                p = p->next;
    
            p->next = t;
        }
    
        //逆邻接表打十字
        if (head[i].to == NULL)
        {
            head[i].to = t;
            return 0;
        }else
        {
            p = head[i].to;
    
            while (p->next != NULL)
                p = p->next;
    
            p->next = t;
        }
    
        return 0;
    }
    
    int main()
    {
        int i,n;
    	
    	memset (head,0,sizeof (head));
        //建图
        scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            add3 (a,b,w);
        }
        return 0;
    }


    邻接多重表(无向图)

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //邻接多重表(无向图)
    
    struct dot
    {
        int i,j;
        int w;
        struct dot *inext;
        struct dot *jnext;
    };
    
    struct hed
    {
        int v;
        struct dot *next;
    }head[100];
    
    int add4(int i,int j,int w)
    {
        struct dot *t = new dot;
        struct dot *p = NULL,*tp = NULL;
    
        t->i = i;
        t->j = j;
        t->w = w;
        t->inext = NULL;
        t->jnext = NULL;
    
        if (head[i].next == NULL)
        {
            head[i].next = t;
        }else
        {
            p = head[i].next;
    
            while (p != NULL)
            {
                tp = p;
                if (p->i == i)
                    p = p->inext;
                else
                    p = p->jnext;
            }
    
                if (tp->i == i)
                    tp->inext = t;
                else
                    tp->jnext = t;
        }
    
        if (head[j].next == NULL)
        {
            head[j].next = t;
        }else
        {
            p = head[j].next;
    
            while (p != NULL)
            {
                tp = p;
                if (p->i == j)
                    p = p->inext;
                else
                    p = p->jnext;
            }
    
            if (tp->i == j)
                    tp->inext = t;
                else
                    tp->jnext = t;
        }
    
        return 0;
    }
    
    int main()
    {
        int i,n;
    
        memset (head,0,sizeof (head));
        //建图
        scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            add4 (a,b,w);
        }
        return 0;
    }
    

    边集数组

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //边集数组
    
    struct e
    {
        int i,j;
        int w;
        
    }eg[100];
    
    int cont;
    
    int add5(int i,int j,int w)
    {
        eg[cont].i = i;
        eg[cont].j = j;
        eg[cont].w = w;
        return 0;
    }
    
    int main()
    {
        int i,n;
    	
    	memset (eg,0,sizeof (eg));
    	cont = 0;
        //建图
        scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            //有向图无向图皆可
            add5 (a,b,w);
        }
        return 0;
    }


    边集数组之前向星

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    //前向星
    int head[100];
    
    struct e
    {
        int to;
        int fro;
        int w;
    }eg[100];
    
    int cont;
    int add6 (int i,int j,int w)
    {
        eg[cont].to = j;
        eg[cont].fro = head[i];
        eg[cont].w = w;
        head[i] = cont++;
    	return 0;
    }
    
    int main()
    {
        int i,n;
    
        memset (head,-1,sizeof (head));
        cont = 0;
        //建图
    	scanf ("%d",&n);
        for (i = 0;i < n;i++)
        {
            int a,b,w;
            //输入起点、终点、权重
            scanf ("%d%d%d",&a,&b,&w);
            add6 (a,b,w);
            //无向图加上
            add6 (b,a,w);
        }
        return 0;
    }
    


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  • 原文地址:https://www.cnblogs.com/yxwkf/p/5281391.html
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