【超详细】MySQL学习笔记汇总（三）之进阶1、2测试

MySQL学习笔记汇总（三）

四、进阶1、2测试题

1、查询工资大于12000 的员工姓名和工资

select 
	last_name,
	salary
from 
	employees
where 
	salary > 12000; 

2、查询员工号为176 的员工的姓名和部门号和年薪

select 
	employee_id,
	last_name,
	department_id,
	salary * 12*(1+IFNULL(commission_pct,0)) as 年薪
FROM 
	employees
where 
	employee_id = 176;

3、选择工资不在5000 到12000 的员工的姓名和工资

select 
	last_name,
	salary,
from 
	employees
where 
    not (salary between 5000 and 1200); 

4、选择在20 或50 号部门工作的员工姓名和部门号

select 
	last_name,
 	department_id 
from 
	employees
where 
	#department_id in (20,50);
	department_id  = 20  or  department_id= 50;

5、选择公司中没有管理者的员工姓名及 job_id

select 
  last_name,
  job_id
from 
  employees
WHERE 
  manager_id is null;

6、选择公司中有奖金的员工姓名，工资和奖金级别

select 
  last_name,
  salary,
  commission_pct
from 
  employees
where 
  commission_pct is not null;

7、选择员工姓名的第三个字母是 a 的员工姓名

select  
 	* 
from 
	(select 
 		CONCAT(first_name,last_name)  as 姓名
	from 
		employees) T 
where 
	T.姓名 like '__a%';

8、选择姓名中有字母 a 和 e 的员工姓名

SELECT 
  last_name
from 
  employees
where 
  last_name like '%a%' and last_name like '%e%' ; 

9、显示出表employees 表中 first_name 以 'e'结尾的员工信息

SELECT 
  first_name
from 
  employees
where 
  first_name like '%e';

10、显示出表employees 部门编号在80-100 之间 的姓名、职位

select 
   last_name,
   job_id,
   department_id
from 
   employees
where 
   department_id between 80 and 100;

11、显示出表employees 的manager_id 是 100,101,110 的员工姓名、职位

select 
	last_name,
	job_id,
	manager_id
from 
    employees
where 
    manager_id in(100,101,110);

12、查询没有奖金，且工资小于18000的salary，last_name

select  
    salary,
    last_name
from 
    employees
where 
    commission_pct is null and salary < 18000;

13、查询job_id不为'IT' 或者 工资为12000的员工信息；

select
	* 
from 
   employees
where  
   job_id <> 'IT' or salary = 12000;