题目意思:
1,给你一个n代表要工作的总月数
2,给你工人的雇佣工资hire,月工资salary,解雇工资fire
3,给你每个月需要的工人数
求最小费用
dp[i][j]代表第i个月使用j个工人的最小费用
#include <stdio.h> int man[15]; int dp[15]; #define INF 0x7FFFFFFF int main() { int month,i; int hire,salary,fire,temp; while(scanf("%d",&month)==1&&month) { scanf("%d%d%d",&hire,&salary,&fire); for(i=1;i<=month;i++) scanf("%d",&man[i]); man[0] = 0; for(int i=1;i<=month;i++) { dp[i] = INF; temp = 0; for(int j=i-1;j>=0;j--) { if(temp > man[i]) break; if(man[j]<temp) continue; temp = man[j]; int newcost; if(temp >= man[i]) { newcost = dp[j] + fire * (temp-man[i]) + salary * (i-j) * man[i]; } else { newcost = dp[j] + hire * (man[i]-temp) + salary * (i-j-1) * temp + salary * man[i]; } if(dp[i] > newcost) dp[i] = newcost; } //printf("dp[%d] = %d\n",i,dp[i]); } dp[month+1] = INF; temp = 0; for(int j=month;j>0;j--) { if(man[j]<temp) continue; temp = man[j]; int newcost = dp[j] + salary * (month-j) * temp; if(dp[month+1] > newcost) dp[month+1] = newcost; } printf("%d\n",dp[month+1]); } return 0; }