zoukankan      html  css  js  c++  java
  • hdu 1058:Humble Numbers(动态规划 DP)

    Humble Numbers

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 14584    Accepted Submission(s): 6313


    Problem Description
    A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... shows the first 20 humble numbers. 

    Write a program to find and print the nth element in this sequence
     
    Input
    The input consists of one or more test cases. Each test case consists of one integer n with 1 <= n <= 5842. Input is terminated by a value of zero (0) for n.
     
    Output
    For each test case, print one line saying "The nth humble number is number.". Depending on the value of n, the correct suffix "st", "nd", "rd", or "th" for the ordinal number nth has to be used like it is shown in the sample output.
     
    Sample Input
    1
    2
    3
    4
    11
    12
    13
    21
    22
    23
    100
    1000
    5842
    0
     
    Sample Output
    The 1st humble number is 1.
    The 2nd humble number is 2.
    The 3rd humble number is 3.
    The 4th humble number is 4.
    The 11th humble number is 12.
    The 12th humble number is 14.
    The 13th humble number is 15.
    The 21st humble number is 28.
    The 22nd humble number is 30.
    The 23rd humble number is 32.
    The 100th humble number is 450.
    The 1000th humble number is 385875.
    The 5842nd humble number is 2000000000.
      
    Source
     
    Recommend
    JGShining   |   We have carefully selected several similar problems for you:  1069 1087 1176 1024 1203 

     
      简单动态规划问题。
      思路是后面的Humble数总可以用前面求得的某个Humble数乘以{2,3,5,7}中的一个求得。
      需要注意的是输出需要按序数的规则输出,个位数是1、2、3的后缀分别是st、nd、rd,但是后两位为11、12、13的数例外(例如11、12、13、111、112、113),它们的后缀是th。其余数后缀均为th。
     
     1 #include <iostream>
     2 using namespace std;
     3 int a[6000];
     4 int Min(int a,int b,int c,int d)
     5 {
     6     int t;
     7     t = a<b?a:b;
     8     t = t<c?t:c;
     9     t = t<d?t:d;
    10     return t;
    11 }
    12 int main()
    13 {
    14     int n;
    15     a[1] = 1;
    16     int a1=1,a2=1,a3=1,a4=1;
    17     int e1,e2,e3,e4;
    18     for(int i=2;i<6000;i++){
    19         e1 = a[a1]*2;
    20         e2 = a[a2]*3;
    21         e3 = a[a3]*5;
    22         e4 = a[a4]*7;
    23         a[i] = Min(e1,e2,e3,e4);
    24         if(a[i]==e1)
    25             a1++;
    26         if(a[i]==e2)
    27             a2++;
    28         if(a[i]==e3)
    29             a3++;
    30         if(a[i]==e4)
    31             a4++;
    32     }
    33     while(cin>>n){
    34         if(n==0)
    35             break;
    36         if(n%100==11 || n%100==12 || n%100==13)
    37             cout<<"The "<<n<<"th humble number is "<<a[n]<<'.'<<endl;
    38         else {
    39             int t = n%10;
    40             switch(t){
    41                 case 0:cout<<"The "<<n<<"th humble number is "<<a[n]<<'.'<<endl;break;
    42                 case 1:cout<<"The "<<n<<"st humble number is "<<a[n]<<'.'<<endl;break;
    43                 case 2:cout<<"The "<<n<<"nd humble number is "<<a[n]<<'.'<<endl;break;
    44                 case 3:cout<<"The "<<n<<"rd humble number is "<<a[n]<<'.'<<endl;break;
    45                 default:cout<<"The "<<n<<"th humble number is "<<a[n]<<'.'<<endl;break;
    46             }
    47         }
    48     }
    49     return 0;
    50 }

    Freecode : www.cnblogs.com/yym2013

  • 相关阅读:
    输入年月日,输出这一天是这一年的多少天
    判断体重是否标准 男标准=身高-100±3 女标准=身高-110±3
    if 条件运算符
    24小时换算成12小时&&判断正负数
    运算符(编程)
    定义变量
    基础知识
    java线程阻塞中断与LockSupport使用介绍(转)
    01背包问题--动态规划解法(2)(转载)
    01背包问题--动态规划解法
  • 原文地址:https://www.cnblogs.com/yym2013/p/3532953.html
Copyright © 2011-2022 走看看