Just a Numble
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2107 Accepted Submission(s): 987
Problem Description
Now give you two integers n m, you just tell me the m-th number after radix point in 1/n,for example n=4,the first numble after point is 2,the second is 5,and all 0 followed
Input
Each line of input will contain a pair of integers for n and m(1<=n<=10^7,1<=m<=10^5)
Output
For each line of input, your program should print a numble on a line,according to the above rules
Sample Input
4 2
5 7
123 123
Sample Output
5
0
8
Author
YBB
Source
Recommend
水题，但也要动动脑子。
模拟除法的运算。输入两个数n和m，求出1/n的小数点后的第m位数。
代码：
1 #include <iostream>
2
3 using namespace std;
4 int main()
5 {
6 int n,m;
7 while(cin>>n>>m){
8 if(n==1){
9 cout<<0<<endl;
10 continue;
11 }
12 int num = 10;
13 int d = 0;
14 int dn = 0;
15 while(d!=m){
16 dn = num/n;
17 num = num%n;
18 num*=10;
19 ++d;
20 }
21 cout<<dn<<endl;
22 }
23 return 0;
24 }
Freecode : www.cnblogs.com/yym2013