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  • UVA 514 Rails

    题目链接:https://vjudge.net/problem/UVA-514

    题目大意

      多组数据,每组数据以 0 结束,每组数据给定 n 个数(1~n,n <= 1000),顺序排列,再给定多组序列,如果一个序列是这 n 个数顺序进栈后合法的出栈序列,则输出“Yes”,否则输出“No”。

    分析

      正解应该是用栈模拟,但这题有邪道解法。
      如果我们遍历到出现序列的第 i 项 ai(前面 i - 1 项都合法),那么如果前面 i - 1 项出现过值为 ai + 1 的元素或前面 i - 1 项的最大值小于 ai ,那么前面 i 项都合法。

    代码如下

      1 #include <bits/stdc++.h>
      2 using namespace std;
      3  
      4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
      5 #define Rep(i,n) for (int i = 0; i < (n); ++i)
      6 #define For(i,s,t) for (int i = (s); i <= (t); ++i)
      7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i)
      8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
      9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
     10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
     11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
     12  
     13 #define pr(x) cout << #x << " = " << x << "  "
     14 #define prln(x) cout << #x << " = " << x << endl
     15  
     16 #define LOWBIT(x) ((x)&(-x))
     17  
     18 #define ALL(x) x.begin(),x.end()
     19 #define INS(x) inserter(x,x.begin())
     20  
     21 #define ms0(a) memset(a,0,sizeof(a))
     22 #define msI(a) memset(a,inf,sizeof(a))
     23 #define msM(a) memset(a,-1,sizeof(a))
     24 
     25 #define MP make_pair
     26 #define PB push_back
     27 #define ft first
     28 #define sd second
     29  
     30 template<typename T1, typename T2>
     31 istream &operator>>(istream &in, pair<T1, T2> &p) {
     32     in >> p.first >> p.second;
     33     return in;
     34 }
     35  
     36 template<typename T>
     37 istream &operator>>(istream &in, vector<T> &v) {
     38     for (auto &x: v)
     39         in >> x;
     40     return in;
     41 }
     42  
     43 template<typename T1, typename T2>
     44 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
     45     out << "[" << p.first << ", " << p.second << "]" << "
    ";
     46     return out;
     47 }
     48 
     49 inline int gc(){
     50     static const int BUF = 1e7;
     51     static char buf[BUF], *bg = buf + BUF, *ed = bg;
     52     
     53     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
     54     return *bg++;
     55 } 
     56 
     57 inline int ri(){
     58     int x = 0, f = 1, c = gc();
     59     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
     60     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
     61     return x*f;
     62 }
     63  
     64 typedef long long LL;
     65 typedef unsigned long long uLL;
     66 typedef pair< double, double > PDD;
     67 typedef pair< int, int > PII;
     68 typedef pair< int, PII > PIPII;
     69 typedef pair< string, int > PSI;
     70 typedef pair< int, PSI > PIPSI;
     71 typedef set< int > SI;
     72 typedef vector< int > VI;
     73 typedef vector< VI > VVI;
     74 typedef vector< PII > VPII;
     75 typedef map< int, int > MII;
     76 typedef map< int, PII > MIPII;
     77 typedef map< string, int > MSI;
     78 typedef multimap< int, int > MMII;
     79 typedef unordered_map< int, int > uMII;
     80 typedef pair< LL, LL > PLL;
     81 typedef vector< LL > VL;
     82 typedef vector< VL > VVL;
     83 typedef priority_queue< int > PQIMax;
     84 typedef priority_queue< int, VI, greater< int > > PQIMin;
     85 const double EPS = 1e-10;
     86 const LL inf = 0x7fffffff;
     87 const LL infLL = 0x7fffffffffffffffLL;
     88 const LL mod = 1e9 + 7;
     89 const int maxN = 1e3 + 7;
     90 const LL ONE = 1;
     91 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
     92 const LL oddBits = 0x5555555555555555;
     93 
     94 int n, vis[maxN];
     95 int maxT; 
     96 bool ans;
     97  
     98 int main(){
     99     //freopen("MyOutput.txt","w",stdout);
    100     INIT();
    101     while(cin >> n) {
    102         if(0 == n) break;
    103         
    104         while(1) {
    105             ans = true;
    106             int x;
    107             maxT = -1;
    108             ms0(vis);
    109             
    110             For(i, 1, n) {
    111                 cin >> x;
    112                 if(0 == x) break;
    113                 if(vis[x + 1]) vis[x] = 1;
    114                 else if(maxT < x) {
    115                     vis[x] = 1;
    116                     maxT = x;
    117                 }
    118                 else ans = false;
    119             }
    120             
    121             if(x == 0) break;
    122             if(ans) cout << "Yes" << endl;
    123             else cout << "No" << endl;
    124         }
    125         cout << endl;
    126     }
    127     return 0;
    128 }
    View Code
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  • 原文地址:https://www.cnblogs.com/zaq19970105/p/10968352.html
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