牛客 遍历二叉树的神级方法

题目链接：https://www.nowcoder.com/practice/5abcb95fe19d475a989dac3ba53e4635?tpId=101&tqId=33232&tPage=1&rp=1&ru=/ta/programmer-code-interview-guide&qru=/ta/programmer-code-interview-guide/question-ranking

题目大意

　　略。

分析

　　线索二叉树 Morris 遍历。

　　获取反转的右边界的时候我还是用了栈，比较方便，实际上应该反转两次链表，这样才能做到空间复杂度 O(1)。

代码如下

#include <bits/stdc++.h>
using namespace std;
 
#define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define Rep(i,n) for (int i = 0; i < (int)(n); ++i)
#define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i)
#define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i)
#define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
#define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
#define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
#define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
 
#define pr(x) cout << #x << " = " << x << "  "
#define prln(x) cout << #x << " = " << x << endl
 
#define LOWBIT(x) ((x)&(-x))
 
#define ALL(x) x.begin(),x.end()
#define INS(x) inserter(x,x.begin())
#define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
#define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 
#define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
#define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
 
#define ms0(a) memset(a,0,sizeof(a))
#define msI(a) memset(a,0x3f,sizeof(a))
#define msM(a) memset(a,-1,sizeof(a))

#define MP make_pair
#define PB push_back
#define ft first
#define sd second
 
template<typename T1, typename T2>
istream &operator>>(istream &in, pair<T1, T2> &p) {
    in >> p.first >> p.second;
    return in;
}
 
template<typename T>
istream &operator>>(istream &in, vector<T> &v) {
    for (auto &x: v)
        in >> x;
    return in;
}

template<typename T>
ostream &operator<<(ostream &out, vector<T> &v) {
    Rep(i, v.size()) out << v[i] << " 
"[i == v.size() - 1];
    return out;
}
 
template<typename T1, typename T2>
ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
    out << "[" << p.first << ", " << p.second << "]" << "
";
    return out;
}

inline int gc(){
    static const int BUF = 1e7;
    static char buf[BUF], *bg = buf + BUF, *ed = bg;
    
    if(bg == ed) fread(bg = buf, 1, BUF, stdin);
    return *bg++;
} 

inline int ri(){
    int x = 0, f = 1, c = gc();
    for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
    for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
    return x*f;
}

template<class T>
inline string toString(T x) {
    ostringstream sout;
    sout << x;
    return sout.str();
}

inline int toInt(string s) {
    int v;
    istringstream sin(s);
    sin >> v;
    return v;
}

//min <= aim <= max
template<typename T>
inline bool BETWEEN(const T aim, const T min, const T max) {
    return min <= aim && aim <= max;
}
 
typedef long long LL;
typedef unsigned long long uLL;
typedef vector< int > VI;
typedef vector< bool > VB;
typedef vector< char > VC;
typedef vector< double > VD;
typedef vector< string > VS;
typedef vector< LL > VL;
typedef vector< VI > VVI;
typedef vector< VB > VVB;
typedef vector< VS > VVS;
typedef vector< VL > VVL;
typedef vector< VVI > VVVI;
typedef vector< VVL > VVVL;
typedef pair< int, int > PII;
typedef pair< LL, LL > PLL;
typedef pair< int, string > PIS;
typedef pair< string, int > PSI;
typedef pair< string, string > PSS;
typedef pair< double, double > PDD;
typedef vector< PII > VPII;
typedef vector< PLL > VPLL;
typedef vector< VPII > VVPII;
typedef vector< VPLL > VVPLL;
typedef vector< VS > VVS;
typedef map< int, int > MII;
typedef unordered_map< int, int > uMII;
typedef map< LL, LL > MLL;
typedef map< string, int > MSI;
typedef map< int, string > MIS;
typedef set< int > SI;
typedef stack< int > SKI;
typedef deque< int > DQI;
typedef queue< int > QI;
typedef priority_queue< int > PQIMax;
typedef priority_queue< int, VI, greater< int > > PQIMin;
const double EPS = 1e-8;
const LL inf = 0x7fffffff;
const LL infLL = 0x7fffffffffffffffLL;
const LL mod = 1e9 + 7;
const int maxN = 1e6 + 7;
const LL ONE = 1;
const LL evenBits = 0xaaaaaaaaaaaaaaaa;
const LL oddBits = 0x5555555555555555;

struct TreeNode {
    int lch = 0, rch = 0;
};

int N, root;
TreeNode tree[maxN];

// 返回搜索二叉树最大值节点的序号 
int getMax(int rt, int cur) {
    while(tree[rt].rch && tree[rt].rch != cur) rt = tree[rt].rch;
    return rt;
}

void getReverseRightEdge(int rt,VI &ret) {
    SKI sk;
    while(rt) {
        sk.push(rt);
        rt = tree[rt].rch;
    }
    while(!sk.empty()) {
        ret.PB(sk.top());
        sk.pop();
    }
}

// mode = 1:先序
// mode = 2:中序
// mode = 3:后序 
void Morris(int rt, int mode) {
    if(rt == 0) return;
    int cur = rt;
    int mostRight = -1;
    VI ret;
    
    while(cur) {
        if(tree[cur].lch) {
            mostRight = getMax(tree[cur].lch, cur);
            
            if(tree[mostRight].rch == cur) { // 第二次来到cur 
                tree[mostRight].rch = 0;
                if(mode == 2) ret.PB(cur);
                if(mode == 3) getReverseRightEdge(tree[cur].lch, ret);
            }
            else { // 第一次来到cur 
                if(mode == 1) ret.PB(cur);
                tree[mostRight].rch = cur;
                cur = tree[cur].lch;
                continue;
            }
        }
        else if(mode != 3) ret.PB(cur);
        cur = tree[cur].rch;
    }
    if(mode == 3) getReverseRightEdge(rt, ret);
    
    Rep(i, ret.size()) printf("%d%c", ret[i], " 
"[i == ret.size() - 1]);
}

int main(){
    //freopen("MyOutput.txt","w",stdout);
    //freopen("input.txt","r",stdin);
    //INIT();
    scanf("%d%d", &N, &root);
    Rep(i, N) {
        int fa, lch, rch;
        scanf("%d%d%d", &fa, &lch, &rch);
        
        tree[fa].lch = lch;
        tree[fa].rch = rch;
    }
    
    Morris(root, 1);
    Morris(root, 2);
    Morris(root, 3);
    return 0;
}