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  • 【bzoj1798】【AHOI2009】维护序列

    练一下线段树模板,区间乘法。

    #include<bits/stdc++.h>
    #define lson (o<<1)
    #define rson (o<<1|1)
    const int N=100010;
    using namespace std;
    typedef long long ll;
    ll n,m,yql;
    ll a[N];
    struct Segment_Tree{
        ll sumv[N<<2],addv[N<<2],mulv[N<<2];
        inline void pushup(int o){sumv[o]=(sumv[lson]+sumv[rson])%yql;}
        inline void pushdown(int o,int l,int r){
            if(mulv[o]==1&&addv[o]==0)return;
            int mid=(l+r)>>1;
            mulv[lson]=mulv[lson]*mulv[o]%yql;
            mulv[rson]=mulv[rson]*mulv[o]%yql;
            addv[lson]=(addv[lson]*mulv[o]%yql+addv[o])%yql;
            addv[rson]=(addv[rson]*mulv[o]%yql+addv[o])%yql;
            sumv[lson]=((sumv[lson]*mulv[o])%yql+addv[o]*1LL*(mid-l+1)%yql)%yql;
            sumv[rson]=((sumv[rson]*mulv[o])%yql+addv[o]*1LL*(r-mid)%yql)%yql;
            mulv[o]=1;addv[o]=0;
        }
        inline void build(int o,int l,int r){
            mulv[o]=1;addv[o]=0;sumv[o]=0;
            if(l==r){sumv[o]=a[l];return;}
            int mid=(l+r)>>1;
            build(lson,l,mid);build(rson,mid+1,r);
            pushup(o);
        }
        inline void mul(int o,int l,int r,int ql,int qr,int v){
            if(ql<=l&&r<=qr){
                mulv[o]=mulv[o]*1LL*v%yql;
                addv[o]=addv[o]*1LL*v%yql;
                sumv[o]=sumv[o]*1LL*v%yql;
                return;
            }
            pushdown(o,l,r);
            int mid=(l+r)>>1;
            if(ql<=mid)mul(lson,l,mid,ql,qr,v);
            if(qr>mid)mul(rson,mid+1,r,ql,qr,v);
            pushup(o);
        }
        inline void add(int o,int l,int r,int ql,int qr,int v){
            if(ql<=l&&r<=qr){
                addv[o]=(addv[o]+1LL*v)%yql;
                sumv[o]=(sumv[o]+1LL*(r-l+1)*v%yql)%yql;
                return;
            }
            pushdown(o,l,r);
            int mid=(l+r)>>1;
            if(ql<=mid)add(lson,l,mid,ql,qr,v);
            if(qr>mid)add(rson,mid+1,r,ql,qr,v);
            pushup(o);
        }
        inline ll querysum(int o,int l,int r,int ql,int qr){
            if(ql<=l&&r<=qr)return sumv[o];
            int mid=(l+r)>>1;ll ans=0;
            pushdown(o,l,r);
            if(ql<=mid)ans+=querysum(lson,l,mid,ql,qr),ans%=yql;
            if(qr>mid)ans+=querysum(rson,mid+1,r,ql,qr),ans%=yql;
            return ans;
        }
    }T;
    inline ll read(){
        ll f=1,x=0;char ch;
        do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');
        do{x=x*10+ch-'0';ch=getchar();}while(ch>='0'&&ch<='9');
        return f*x;
    }
    int main(){
        n=read();yql=read();
        for(int i=1;i<=n;i++)a[i]=read();
        T.build(1,1,n);
        m=read();
        while(m--){
            ll opt=read();
            if(opt==1){int l=read(),r=read(),x=read();T.mul(1,1,n,l,r,x);}
            if(opt==2){int l=read(),r=read(),x=read();T.add(1,1,n,l,r,x);}
            if(opt==3){int l=read(),r=read();printf("%lld
    ",T.querysum(1,1,n,l,r));}
        }
    }
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  • 原文地址:https://www.cnblogs.com/zcysky/p/7360316.html
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