1.一道SQL语句面试题，关于group by表内容：
info 表
date result
2005-05-09 win
2005-05-09 lose
2005-05-09 lose
2005-05-09 lose
2005-05-10 win
2005-05-10 lose
2005-05-10 lose
如果要生成下列结果, 该如何写sql语句?
win lose
2005-05-09 2 2
2005-05-10 1 2
答案：
(1) select date, sum(case when result = "win" then 1 else 0 end) as "win", sum(case when result = "lose" then 1 else 0 end) as "lose" from info group by date;
(2) select a.date, a.result as win, b.result as lose
from
(select date, count(result) as result from info where result = "win" group by date) as a
join
(select date, count(result) as result from info where result = "lose" group by date) as b
on a.date = b.date;
2.表中有A B C三列,用SQL语句实现：当A列大于B列时选择A列否则选择B列，当B列大于C列时选择B列否则选择C列
select (case when a > b then a else b end), (case when b > c then b else c end) from table;
3.请取出tb_send表中日期(SendTime字段)为当天的所有记录? (SendTime字段为datetime型，包含日期与时间)
------------------------------------------
select * from tb where datediff(dd,SendTime,getdate())=0
4.有一张表，里面有3个字段：chinese，math，english。其中有一条记录chinese 70分，math 80分，english 58分，请用一条sql语句查询出所有记录并按以下条件显示出来（并写出您的思路）：
大于或等于80表示excellent，大于或等于60表示pass，小于60分表示fail。
显示格式： 以上面的chinese 70分，math 80分，english 58分
chinese math english
pass excellent fail
select (case when chinese >= 80 then "excellent" when chinese >= 60 then "pass" else "fail" end) as chinese,
(case when math >= 80 then "excellent" when math >= 60 then "pass" else "fail" end) as math,
(case when english >= 80 then "excellent" when english >= 60 then "pass" else "fail" end) as english
from grade;
5.请用一个sql语句得出结果
从table1,table2中取出如table3所列格式数据，注意提供的数据及结果不准确，只是作为一个格式向大家请教。
如使用存储过程也可以。
table1
月份mon 部门dep 业绩yj
-------------------------------
一月份 01 10
一月份 02 10
一月份 03 5
二月份 02 8
二月份 04 9
三月份 03 8
table2
部门dep 部门名称dname
--------------------------------
01 国内业务一部
02 国内业务二部
03 国内业务三部
04 国际业务部
table3 （result）
部门dep 一月份 二月份 三月份
--------------------------------------
01 10 null null
02 10 8 null
03 null 5 8
04 null null 9
------------------------------------------
select t1.dep,
sum(case when mon = 1 then yj else 0 end) as jun,
sum(case when mon = 2 then yj else 0 end) as feb,
sum(case when mon = 3 then yj else 0 end) as mar
from
t1 right join t2 on t1.dep = t2.dep
group by t1.dep;