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  • 牛客网补题 New Game!(原Wannafly summer camp day2原题)

    思路:这个题在秦皇岛的时候好像没有写出来,反正我是没有写出来,题解是听懂了;把直线和圆都看做一个结点,圆和直线用点到直线的距离与半径差求出来,圆和圆之间用点和点之间的距离和半径差表示,最后最短路跑一遍就行了。

    #include<cstdio>
    #include<vector>
    #include<cmath>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    #define ll long long
    #define inf 0x3f3f3f3f
    using namespace std;
    int vis[1005];
    double mlen[1005];
    const double maxn = 1e9 + 10;
    double map[1005][1005];
    int n, a, b, c1, c2;
    struct Node{
        int x, y, r;
        Node(){}
        Node(int _x, int _y, int _r) :x(_x), y(_y), r(_r){}
    }ya[1005];
    
    void dijkstra(){
        memset(vis, 0, sizeof vis);
        
        for (int i = 0; i <= n + 1; i++)
            mlen[i] = map[0][i];
        mlen[0] = 0;
        /*for (int i = 0; i <= n + 1; i++)
            cout << mlen[i] << " * ";
            */
        for (int t = 0; t <= n + 1; t++){
            double ma = maxn; int p;
            for (int i = 0; i <= n + 1; i++){
                if (mlen[i] <= ma&&!vis[i]){ ma = mlen[i]; p = i; }
            }
            vis[p] = 1;
            //cout << mlen[p] << " " << p << endl;
            for (int i = 0; i <= n + 1; i++){
                if (p != i&&!vis[i] && mlen[p] + map[p][i] < mlen[i]){
                    mlen[i] = mlen[p] + map[p][i];
                    //cout << p << " " << i << " " << mlen[i] << endl;
                }
            }
        }
    }
    int main(){
        
        //memset(map, maxn, sizeof map);
        
        vector<Node>vec;
    
        scanf("%d%d%d%d%d", &n, &a, &b, &c1, &c2);
        
        map[0][n + 1] = map[n + 1][0] = abs(c1 - c2)*1.0 / sqrt(a*a + b*b);
        for (int i = 0; i <= n + 1; i++)
        for (int j = 0; j <= n + 1; j++)
            map[i][j] = maxn;
    
        int x, y, r;
        for (int i = 1; i <= n; i++){
            scanf("%d%d%d", &x, &y, &r);
            vec.push_back(Node(x, y, r));
        }
        
        for (int i = 0; i < vec.size(); i++){
            double len = abs(a*vec[i].x + b*vec[i].y + c1)*1.0 / sqrt(a*a + b*b) - vec[i].r*1.0;
            if (len < 0)len = 0;
            map[0][i + 1] = len;
            map[i + 1][0] = len;
        }
        for (int i = 0; i < vec.size(); i++){
            double len = abs(a*vec[i].x + b*vec[i].y + c2)*1.0 / sqrt(a*a + b*b) - vec[i].r*1.0;
            if (len < 0)len = 0;
            map[n+1][i + 1] = len;
            map[i + 1][n+1] = len;
        }
    
        for (int i = 0; i < n; i++){
            for (int j = i + 1; j < n; j++){
                double len = sqrt(pow(vec[i].x - vec[j].x, 2) + pow(vec[i].y - vec[j].y, 2));
                len = len - vec[i].r - vec[j].r;
                if (len < 0)len = 0;
                map[i + 1][j + 1] = len;
                map[j + 1][i + 1] = len;
            }
        }
        /*for (int i = 0; i <= n + 1; i++){
            for (int j = 0; j <= n + 1; j++)
                cout << map[i][j] << " ";
            cout << endl;
        }*/
        dijkstra();
        printf("%.6lf
    ", mlen[n + 1]);
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zengguoqiang/p/9736131.html
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