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  • Different Ways to Add Parentheses

    241. Different Ways to Add Parentheses

    Total Accepted: 13500 Total Submissions: 43882 Difficulty: Medium

    Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+- and *.

    Example 1

    Input: "2-1-1".

    ((2-1)-1) = 0
    (2-(1-1)) = 2

    Output: [0, 2]


    Example 2

    Input: "2*3-4*5"

    (2*(3-(4*5))) = -34
    ((2*3)-(4*5)) = -14
    ((2*(3-4))*5) = -10
    (2*((3-4)*5)) = -10
    (((2*3)-4)*5) = 10

    Output: [-34, -14, -10, -10, 10]

     
    class Solution {
    public:
        vector<int> diffWaysToCompute(string input) {
            vector<int> res;
            int input_size = input.size();
            for(int i=0;i<input_size;i++){
                if(!isdigit(input[i])){
                    vector<int> res1 = diffWaysToCompute(input.substr(0,i));
                    vector<int> res2 = diffWaysToCompute(input.substr(i+1));
                    for(auto num1 : res1){
                        for(auto num2:res2){
                            switch(input[i]){
                                case '+' : res.push_back(num1+num2) ;break;
                                case '-' : res.push_back(num1-num2) ;break;
                                case '*' : res.push_back(num1*num2) ;break;
                            }
                        }
                    }
                }
            }
            if(res.empty()){
                res.push_back(stoi(input));
            }
            return res;
        }
    };
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  • 原文地址:https://www.cnblogs.com/zengzy/p/5059282.html
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