zoukankan      html  css  js  c++  java
  • BestCoder Round #34B——数学——Building Blocks

    Problem Description

    After enjoying the movie,LeLe went home alone. LeLe decided to build blocks. LeLe has already built n piles. He wants to move some blocks to make W consecutive piles with exactly the same height H.

    LeLe already put all of his blocks in these piles, which means he can not add any blocks into them. Besides, he can move a block from one pile to another or a new one,but not the position betweens two piles already exists.For instance,after one move,"3 2 3" can become "2 2 4" or "3 2 2 1",but not "3 1 1 3".

    You are request to calculate the minimum blocks should LeLe move.

    Input

    There are multiple test cases, about 100 cases.

    The first line of input contains three integers n,W,H(1n,W,H50000).n indicate n piles blocks.

    For the next line ,there are n integers A1,A2,A3,,An indicate the height of each piles. (1Ai50000)

    The height of a block is 1.

    Output

    Output the minimum number of blocks should LeLe move.

    If there is no solution, output "-1" (without quotes).

    Sample Input
    4 3 2
    1 2 3 5
    4 4 4
    1 2 3 4
    Sample Output
    1
    -1
    Hint
    In first case, LeLe move one block from third pile to first pile.
    大意:搭积木,连续的要3个,高度要是2,共4组,每次放能放到左边或者右边,不能放到两组之间,开long long 
    把区间移动
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    const int inf = 0x3f3f3f3f;
    typedef long long ll;
    int main()
    {
        int n,w,h;
        int a[110];
        while(~scanf("%d%d%d",&n,&w,&h)){
            ll l ,r, sum;
            l = r = sum =0;
            memset(a,0,sizeof(a));
                for(int i = w + 1; i <= w + n;i++){
                    scanf("%d",&a[i]);
                    sum += a[i];
                }
                if(sum < w*h){
                        printf("-1
    ");
                        continue;
                }
                int min1 = inf;
                for(int i = 1; i <= 2*w + n;i++){
                 if(a[i] - h > 0)
                 r += a[i] - h;
                 else  l += a[i] - h;
                 if(i >= w){
                      l = -l;
                     int temp = max(l,r);
                     min1 = min(min1,temp);
                 l = -l;
                if(a[i-w+1]-h > 0)
                r -= a[i-w+1]-h;
                else l -= a[i-w+1] - h;
               }
            }
            printf("%d
    ",min1);
        }
        return 0;
    }
    View Code
  • 相关阅读:
    install_bugzilla
    R610 & R710 网卡问题
    总结开发者在合作过程中的典型交流方式
    vnc报错 font catalog is not properly configured
    eclipse插件安装
    extjs 点击链接到另一个页面 并激活另一个页面的指定tab
    centos c++ 找不到头文件mysql.h
    升级struts 2
    oracle 删除用户报错
    mysql 创建用户及授权
  • 原文地址:https://www.cnblogs.com/zero-begin/p/4363634.html
Copyright © 2011-2022 走看看