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  • HDU5400——Arithmetic Sequence

    http://acm.hdu.edu.cn/showproblem.php?pid=5400

    /************************************************
    * Author        :Powatr
    * Created Time  :2015-8-18 13:00:59
    * File Name     :1005.cpp
     ************************************************/
    
    #include <cstdio>
    #include <algorithm>
    #include <iostream>
    #include <sstream>
    #include <cstring>
    #include <cmath>
    #include <string>
    #include <vector>
    #include <queue>
    #include <deque>
    #include <stack>
    #include <list>
    #include <map>
    #include <set>
    #include <bitset>
    #include <cstdlib>
    #include <ctime>
    using namespace std;
    
    #define lson l, mid, rt << 1
    #define rson mid + 1, r, rt << 1 | 1
    typedef long long ll;
    const int MAXN = 1e5 + 10;
    const int INF = 0x3f3f3f3f;
    const int MOD = 1e9 + 7;
    
    int a[MAXN];
    int pre1[MAXN], pre2[MAXN];
    int main(){
        int n, d1, d2;
        while(~scanf("%d%d%d", &n, &d1, &d2)){
            for(int i = 1; i <= n; i++)
                scanf("%d", &a[i]);
            memset(pre1, 0, sizeof(pre1));
            memset(pre2, 0, sizeof(pre2));
            for(int i = 1; i < n; i++){
                if(a[i+1] - a[i] == d1)
                    pre1[i+1] = pre1[i] + 1;
            }
            for(int i = n; i >= 2; i--){
                if(a[i] - a[i-1] == d2)
                    pre2[i-1] = pre2[i] + 1;
            }
            if(d1 == d2){
                int num = 1;
                ll ans = 0;
                for(int i = 1; i < n; i++){
                    if(a[i+1] - a[i] == d1){
                        num++;
                    }
                    else{
                        ans += 1ll*num*(num+1)/2;
                        num = 1;
                    }
                }
                ans += 1ll*num*(num+1)/2;
                printf("%I64d
    ", ans);
                continue;
            }
            ll ans = 0;
            
            for(int i = 1; i <= n; i++)
                    ans += (1ll*(pre1[i]+1) * 1ll*(pre2[i]+1));
            printf("%I64d
    ", ans);
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/zero-begin/p/4742193.html
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