编程实现:a[0]*b[0] + a[1]*b[1] +...+a[i]*b[j]
>>> a=[1,2,3,4,5]>>> b=[6,7,8,9,0]
>>> from functools import reduce>>> from operator import add,mul>>> reduce(add,map(mul,a,b))80
>>> filter(lambda x:x>2,a)[3, 4, 5]