zoukankan      html  css  js  c++  java
  • Books CodeForces

    When Valera has got some free time, he goes to the library to read some books. Today he's got t free minutes to read. That's why Valera took n books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to n. Valera needs ai minutes to read the i-th book.

    Valera decided to choose an arbitrary book with number i and read the books one by one, starting from this book. In other words, he will first read book number i, then book number i + 1, then book number i + 2 and so on. He continues the process until he either runs out of the free time or finishes reading the n-th book. Valera reads each book up to the end, that is, he doesn't start reading the book if he doesn't have enough free time to finish reading it.

    Print the maximum number of books Valera can read.

    Input

    The first line contains two integers n and t (1 ≤ n ≤ 105; 1 ≤ t ≤ 109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of n integers a1, a2, ..., an (1 ≤ ai ≤ 104), where number ai shows the number of minutes that the boy needs to read the i-th book.

    Output

    Print a single integer — the maximum number of books Valera can read.

    Example

    Input
    4 5
    3 1 2 1
    Output
    3
    Input
    3 3
    2 2 3
    Output
    1

    1.建议学会算法,不懂尽情百度!
     1 #include<iostream>
     2 #include<algorithm>
     3 #include<cstdio>
     4 using namespace std;
     5 
     6 int main()
     7 {  int n,m;
     8    while(~scanf("%d%d",&n,&m)){
     9          int s[n+1];
    10          for(int i=1;i<=n;i++) scanf("%d",&s[i]);
    11          int l=1,r=1;
    12          int ans=0,temp=0;
    13          while(r<=n){
    14               temp+=s[r];
    15               r++;
    16               while(temp>m){
    17                   temp-=s[l];
    18                   l++;              
    19               }
    20               ans=max(ans,r-l);   //更新答案 
    21          }
    22          cout<<ans<<endl;
    23    }
    24 } 
  • 相关阅读:
    回顾2016,工作总结!
    上传base64格式的图片到服务器
    input输入提示历史记录
    input输入时软键盘回车显示搜索
    JS设置和读取Cookie
    正则表达式识别字符串中的URL
    X-Frame-Options配置
    pytest学习笔记
    测试理论基础总结
    redis杂七杂八
  • 原文地址:https://www.cnblogs.com/zgglj-com/p/6743555.html
Copyright © 2011-2022 走看看