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  • Bone Collector HDU

    Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
    The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?


    InputThe first line contain a integer T , the number of cases.
    Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.OutputOne integer per line representing the maximum of the total value (this number will be less than 2 31).Sample Input

    1
    5 10
    1 2 3 4 5
    5 4 3 2 1

    Sample Output

    14

    裸的01背包
     1 #include<iostream>
     2 #include<algorithm>
     3 #include<cstdio>
     4 #include<cstring>
     5 using namespace std;
     6 
     7 int main()
     8 {   int t,n,V;
     9     cin>>t;
    10     while(t--){
    11         scanf("%d%d",&n,&V);
    12         int va[1005],vo[1005],dp[1005];
    13         for(int i=0;i<n;i++) scanf("%d",&va[i]);
    14         for(int i=0;i<n;i++) scanf("%d",&vo[i]);
    15         
    16         memset(dp,0,sizeof(dp));
    17         for(int i=0;i<n;i++){
    18             for(int j=V;j>=vo[i];j--)
    19                 dp[j]=max(dp[j],dp[j-vo[i]]+va[i]);
    20         }
    21         printf("%d
    ",dp[V]);
    22     }
    23 }


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  • 原文地址:https://www.cnblogs.com/zgglj-com/p/6810482.html
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