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  • LeetCode-232.Implement Queue using Stacks

    Implement the following operations of a queue using stacks.

    • push(x) -- Push element x to the back of queue.
    • pop() -- Removes the element from in front of queue.
    • peek() -- Get the front element.
    • empty() -- Return whether the queue is empty.

    Example:

    MyQueue queue = new MyQueue();
    
    queue.push(1);
    queue.push(2);  
    queue.peek();  // returns 1
    queue.pop();   // returns 1
    queue.empty(); // returns false

    Notes:

    • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is empty operations are valid.
    • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
    • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

    使用两个栈,一个输入栈,一个输出栈

    输入O(1),输出O(n)

     1 class MyQueue {//栈 队列 my
     2     Stack<Integer> stack1;
     3     Stack<Integer> stack2;
     4 
     5     /** Initialize your data structure here. */
     6     public MyQueue() {
     7         stack1 = new Stack<Integer>();
     8         stack2= new Stack<Integer>();
     9     }
    10     
    11     /** Push element x to the back of queue. */
    12     public void push(int x) {
    13         stack1.push(x);
    14     }
    15     
    16     /** Removes the element from in front of queue and returns that element. */
    17     public int pop() {
    18         if(stack2.isEmpty()){
    19             while(!stack1.isEmpty()){
    20                 Integer x = stack1.pop();
    21                 stack2.push(x);
    22             }
    23         }
    24         return stack2.pop();
    25     }
    26     
    27     /** Get the front element. */
    28     public int peek() {
    29         if(stack2.isEmpty()){
    30             while(!stack1.isEmpty()){
    31                 Integer x = stack1.pop();
    32                 stack2.push(x);
    33             }
    34         }
    35         return stack2.peek();
    36     }
    37     
    38     /** Returns whether the queue is empty. */
    39     public boolean empty() {
    40         return stack2.isEmpty()&&stack1.isEmpty();
    41     }
    42 }

    相关题

    使用队列实现栈 LeetCode225 https://www.cnblogs.com/zhacai/p/10565181.html

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  • 原文地址:https://www.cnblogs.com/zhacai/p/10565130.html
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