Given a binary tree, find the leftmost value in the last row of the tree.
Example 1:
Input: 2 / 1 3 Output: 1
Example 2:
Input: 1 / 2 3 / / 4 5 6 / 7 Output: 7
public int findBottomLeftValue(TreeNode root) { LinkedList<TreeNode> queue = new LinkedList<>(); queue.offer(root); TreeNode cur = root; while(!queue.isEmpty()){ cur = queue.poll(); if(cur.right!=null){ queue.offer(cur.right); } if(cur.left!=null){ queue.offer(cur.left); } } return cur.val; }