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  • python跨网段遍历枚举IP地址(转)

    转载链接:https://blog.csdn.net/u013042248/article/details/53165508

    0x01 代码思路:

    利用二进制遍历:

    1.将IP地址分割,每一块转换为8位二进制代码

    2.将32位二进制代码转化为十进制,结束地址的十进制减去开地址的十进制,就可以得到之间的IP个数

    3.从开始地址起,对其十进制数依次加一,再将其转化为二进制,即可得到之间某一IP的二进制代码

    4.将这一IP的二进制按8位分割,每8位转化为一个十进制数,加上”.”,即可得到最终的IP

    0x02 代码清单:

    import os,sys
    
    base = [str(x) for x in range(10)] + [ chr(x) for x in range(ord('A'),ord('A')+6)]
    
    #十进制0~255转化为二进制,补0到8位
    def dec2bin80(string_num):
        num = int(string_num)
        mid = []
        while True:
            if num == 0: break
            num,rem = divmod(num, 2)
            mid.append(base[rem])
    
        result = ''.join([str(x) for x in mid[::-1]])
        length = len(result)
        if length < 8:
            result = '0' * (8 - length) + result
        return result
    
    
    #十进制0~255转化为二进制,补0到32位
    def dec2bin320(string_num):
        num = int(string_num)
        mid = []
        while True:
            if num == 0: break
            num,rem = divmod(num, 2)
            mid.append(base[rem])
    
        result = ''.join([str(x) for x in mid[::-1]])
        length = len(result)
        if length < 32:
            result = '0' * (32 - length) + result
        return result
    
    
    #十进制0~255转化为二进制,不补零
    def dec2bin(string_num):
        num = int(string_num)
        mid = []
        while True:
            if num == 0: break
            num,rem = divmod(num, 2)
            mid.append(base[rem])
    
        return ''.join([str(x) for x in mid[::-1]])
    
    
    #二进制转换为十进制
    def bin2dec(string_num):
        return str(int(string_num, 2))
    
    #ip列表生成
    def iplist(string_startip,string_endip):
    
        #分割IP,然后将其转化为8位的二进制代码
        start = string_startip.split('.')
        start_a = dec2bin80(start[0])
        start_b = dec2bin80(start[1])
        start_c = dec2bin80(start[2])
        start_d = dec2bin80(start[3])
        start_bin = start_a + start_b + start_c + start_d
        #将二进制代码转化为十进制
        start_dec = bin2dec(start_bin)
    
        end = string_endip.split('.')
        end_a = dec2bin80(end[0])
        end_b = dec2bin80(end[1])
        end_c = dec2bin80(end[2])
        end_d = dec2bin80(end[3])
        end_bin = end_a + end_b + end_c + end_d
        #将二进制代码转化为十进制
        end_dec = bin2dec(end_bin)
    
        #十进制相减,获取两个IP之间有多少个IP
        count = int(end_dec) - int(start_dec)
    
        #生成IP列表
        for i in range(0,count + 1):
            #将十进制IP加一,再转化为二进制(32位补齐)
            plusone_dec = int(start_dec) + i
            plusone_dec = str(plusone_dec)
            address_bin = dec2bin320(plusone_dec)
            #分割IP,转化为十进制
            address_a = bin2dec(address_bin[0:8])
            address_b = bin2dec(address_bin[8:16])
            address_c = bin2dec(address_bin[16:24])
            address_d = bin2dec(address_bin[24:32])
            address = address_a + '.'+ address_b +'.'+ address_c +'.'+ address_d
            print address
    
    
    iplist('2.168.255.254','2.169.1.10')
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  • 原文地址:https://www.cnblogs.com/zhaijiahui/p/9255657.html
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