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  • [LeetCode283]Move Zeros将一个数组中为0的元素移至数组末尾

    题目:

    Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

    For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

    Note:

    1. You must do this in-place without making a copy of the array.
    2. Minimize the total number of operations.

    思路:可以该数组从后向前遍历,遇到0就把0放至末尾;或者从前遍历遇到非0元素则依次放在数组前,最后将后边元素全部置为0

    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    using System.Threading.Tasks;
    
    namespace LeetCode
    {
        class MoveZerosSolution
        {
            public void MoveZeroes(int[] nums)
            {
                //O(n2)
                for (int i = nums.Length - 1; i >= 0; i--)
                {
                    if (nums[i] == 0)
                    {
                        for (int j = i; j < nums.Length - 1; j++)
                        {
                            nums[j] = nums[j + 1];
                        }
                        nums[nums.Length - 1] = 0;
                    }
    
                }
                /*O(1)解法
            
                int index = 0;
                for(int i = 0;i < nums.Length;i++)
                    if(nums[i] != 0)
                    {
                        nums[index] = nums[i];
                        index++;
                    }
                for(int j = index;j < nums.Length;j++)
                    nums[j] = 0;
            
                */
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/zhangbaochong/p/5059725.html
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