codeforces 669A A. Little Artem and Presents(水题)

题目链接：

A. Little Artem and Presents

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Little Artem got n stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Artem can't give her the same number of stones twice in a row. For example, he can give her 3 stones, then 1 stone, then again 3 stones, but he can't give her 3 stones and then again 3 stones right after that.

How many times can Artem give presents to Masha?

Input

 

The only line of the input contains a single integer n (1 ≤ n ≤ 109) — number of stones Artem received on his birthday.

Output

 

Print the maximum possible number of times Artem can give presents to Masha.

Examples

 

input

1

output

1

input

2

output

1

input

3

output

2

input

4

output

3

Note

In the first sample, Artem can only give 1 stone to Masha.

In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.

In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.

In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and finally 1 stone again.

题意：

问每次给个数,相邻的数不能一样,和为n,怎么才能使次数最多,最多为多少次;

思路：

次数最多,那么就尽量为1和2了;

AC代码：

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod=1e9+7;
const ll inf=1e15;
const int N=1e5+6;

int main()
{

    int n;
    scanf("%d",&n);
    if(n%3==0)printf("%d
",n/3*2);
    else if(n%3==1)printf("%d
",n/3*2+1);
    else
    {
        printf("%d
",n/3*2+1);
    }
    return 0;
}