题目链接:
题意:
给出第i个商店的价钱为x[i],现在询问mi能在多少个地方买酒;
思路:
sort后再二分;
AC代码:
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <map> #include <bits/stdc++.h> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar()); for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + '0'); putchar(' '); } const LL mod=998244353; const double PI=acos(-1.0); const LL inf=1e18; const int N=1e5+10; const int maxn=1e3+10; const double eps=1e-4; int n,a[N]; int main() { read(n); For(i,1,n)read(a[i]); sort(a+1,a+n+1); int q,m; read(q); while(q--) { read(m); int l=1,r=n; while(l<=r) { int mid=(l+r)>>1; if(a[mid]<=m)l=mid+1; else r=mid-1; } printf("%d ",l-1); } return 0; }