zoukankan      html  css  js  c++  java
  • Update data in one table with data from another table

    This blog post illustrates how to update more than one column in a table with values from columns in another table and explains how to do it in the three RDBMS that we support.

    Table Structures and values:

    TableA has four columns: a, b, c, d (a is the primary key column)
    TableB has five columns: a1, b1, c1, d1, e1 (a1 and b1 together constitute the primary key for this table)

    The foreign key relationship between the two tables is based on A.a = B.a1

    The data in these 2 tables is as follows:
    I.    TableA
    a    b    c    d
    1    x    y    z
    2    a    b    c
    3    t    x    z

    II.    TableB
    a1    b1    c1    d1    e1
    1    x1    y1    z1    40
    2    a1    b1    c1    50

    The requirement is to write a SQL to update columns b, c and d in TableA from the columns b1, c1 and d1 from TableB where-ever the join condition satisfies and e1 > 40 in TABLEB.

    Oracle:

    UPDATE TABLEA
    SET (b, c, d) = (SELECT b1, c1, d1 from TABLEB WHERE TABLEB.a1 = TABLEA.a and TABLEB.e1 > 40)
    WHERE EXISTS (SELECT 1 from TABLEB WHERE TABLEB.a1 = TABLEA.a and TABLEB.e1 > 40)
    /

    Results after the update:

    a    b    c    d
    ————————————
    1     x          y           z
    2     a1        b1         c1
    3     t           x           z

    SQL Server:

    UPDATE TABLEA
    SET     b = TABLEB.b1,
    c = TABLEB.c1,
    d = TABLEB.d1
    FROM TABLEA, TABLEB
    WHERE TABLEA.a = TABLEB.a1
    AND TABLEB.e1 > 40
    GO

    Note: This is an extension in SQL Server i.e. the FROM clause – it does make it simple to understand and is a nice feature.

    Results after the update:

    a    b    c    d
    ————————————
    1     x          y           z
    2     a1        b1         c1
    3     t           x           z

    DB2 LUW:

    –Same as Oracle–

    UPDATE TABLEA
    SET (b, c, d) = (SELECT b1, c1, d1 from TABLEB WHERE TABLEB.a1 = TABLEA.a and TABLEB.e1 > 40)
    WHERE EXISTS (SELECT 1 from TABLEB WHERE TABLEB.a1 = TABLEA.a and TABLEB.e1 > 40);

    Results after the update:

    a    b    c    d
    ————————————
    1     x          y           z
    2     a1        b1         c1
    3     t           x           z

    NOTE:

    It is very important to make sure that your where clause for the update statement is correct since that is what identifies the records that the update statement is going to qualify and do the update upon.  If it is incorrect, then you can get wrong results.  The reason I am mentioning this is because I have seen people write wrong where clauses and then wondering what went wrong because they specified the correct condition in the SET clause.

    In the above example, if the Where condition was omitted, the other record’s columns would be updated to NULL value and this will be the final result set:

    a    b    c    d
    ————————————
    1     Null      Null      Null
    2     a1        b1         c1
    3     Null     Null      Null

  • 相关阅读:
    sudo 之后 unable to resolve host的问题解决办法
    Linux 查找具体的文件名称
    linux 访问远程务器代码
    spark 安装配置
    R基本介绍
    BIEE多层表头报表的制作方法
    支付宝新漏洞引发恐慌,那如何关闭小额免密支付呢
    大家注意了,支付宝被曝重大安全漏洞,回应称正在跟进排查
    2017年5个不应该被忽视的机器学习项目
    婚前最后一次加班
  • 原文地址:https://www.cnblogs.com/zhangchenliang/p/2794694.html
Copyright © 2011-2022 走看看